Answer:
import java.util.Scanner;
class Main {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
System.out.print("Enter a decimal value (0 to 15): ");
int num = scan.nextInt();
scan.close();
if (num < 0 || num >15) {
System.out.printf("%d is an invalid input\n", num);
} else {
System.out.printf("The hex value is %X\n", num);
}
}
}
Explanation:
Hopefully this example will get you going for the other assignments.
Answer:
The algorithm to find A is even or odd.
- input A.
- Check the remainder on diving by 2 by A%2.
- If remainder is 1 then A is odd Print(Odd).
- If remainder is 0 print(Even).
Explanation:
To check if the number is even or odd we use modulo operator(%).Which gives the remainder on dividing.So if we do this A%2 it will give the remainder that will come out on dividing the value of A by 2.
So if the remainder comes out is 1 then the number is odd and if the remainder is 0 then the number is odd.
Um I need a image or smth
Answer:
I am going to use the Python programming language to answer this. The source code is given below:
print("Enter your tweet here")
user_tweet = input()
decoded_tweet = user_tweet.replace('TTYL', 'talk to you later')
print("This is the decoded tweet: ")
print(decoded_tweet)
Explanation:
In the program the replace() module was used to replace 'TTYL' with 'talk to you later.'
Attached is the screenshot of the output.
