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Doss [256]
2 years ago
8

0x400C (in hexadecimal)?

Computers and Technology
1 answer:
soldier1979 [14.2K]2 years ago
8 0

Answer:

16396

Explanation:

400C = (4 × 16³) + (0 × 16²) + (0 × 16¹) + (12 × 16⁰) = 16396

https://www.rapidtables.com/convert/number/hex-to-decimal.html

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If userA wants to send a secure message to userB using an asymmetric cryptographic algorithm, which key does userB use to decryp
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Answer:

userB will use his/her private key.

Explanation:

The steps involved in using asymmetric cryptographic algorithm are as follow:

1. Each user generates a pair of keys to be used for the encryption and decryption of messages.

2. Each user places one of the two keys in a public register or other accessible file. This is the public key. The companion key is kept private.

3. If UserA wishes to send a confidential message to UserB, UserA encrypts the message using UserB's public key.

4. When UserB receives the message, she decrypts it using her private key.

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Explain with a few sentences and using the terms sequencing, selections and loops how they
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A wireframe is a sketch detailing where text and images will be placed on a website. T/F
kirill115 [55]
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Which extra step do verizon devices require for fenrir to be allowed to connect to the device?
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8 0
1 year ago
This program is to compute and write to a file the GPA for student scores read from an input file. The point values of the grade
VARVARA [1.3K]

Answer:

#Take input from the user

filename=input('Enter name of input file: ')

total_units=0#Total number of units for a student

total_score=0#Total score of a student

#Assign a score to each grade. I have reduced 0.33 for each grade. Change here if you need to

grade={'A':4.0,'A-':3.67,'B+':3.34,'B':3.01,'B-':2.68,'C+':2.35,'C':2.02,'C-':1.69,'D+':1.36,'D':1.03}

try:

with open(filename,"r") as input_file:#Open the file for input(reading)

output_file=open("GPA_output.txt","w") #Create and open GPA_output.txt if it doesn't exist for writing

for student_record in input_file:#read from input file

if("," in student_record):#if there is a , that means this is the student name

student_name=student_record.strip('\n')#Remove \n from student name

continue

else:

if(" " in student_record):#If a line contains spaces then its the student's grades for a course

student=student_record.split(" ")#Split to find the coursename, units and grade

#student[0]=coursename student[1]=units student[2]=grade

total_units+=int(student[1])#Calculate total units for 1 student

total_score+=int(student[1])*grade[student[2].strip('\n')]#Find the total score of a student

#grade[student[2]] will lookup for the score that we initialized earlier

#if student has a grade as A then this will look up as grade['A'] which will return 4

#Find the total score as product of this grade and units for this course

continue

else:

if(total_units>0):#Check if score has been calculated for a student earlier

print("in")

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

if(total_units>0):#Essential for the case when the file doesn't end with a new line(Check if total_units is not 0) which means a record is pending

#to be written to the file

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

input_file.close()#Close the input file

output_file.close()#Close the output file

except IOError as e:

print("Problem in Opening the required file")#Print a message if file cannot be opened

Explanation:

The program has been tested for all 3 scenarios mentioned i.e.

a. If the file ends without \n

b. If the file ends with 2 \n

c. If the file ends with 1 \n

PS: The Program will run irrespective of how it ends. Even if there are many \n at the end of file, the program will be fine.

3 0
2 years ago
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