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xeze [42]
2 years ago
11

Which of the following data could be graphed using a dot plot? Select all that apply.​

Mathematics
2 answers:
suter [353]2 years ago
8 0

Answer:

You need to provide more information, images data etc.

Step-by-step explanation:

slava [35]2 years ago
7 0

Answer:cars and siblings

Step-by-step explanation:

You might be interested in
Please help!! I'll give brainleist
anygoal [31]

Answer:

m + g < 40

12m + 14g  > 250

Step-by-step explanation:

Given : Jordan is paid $12 per hour for mowing lawns and $14 per hour for planting gardens.

Let m represents the number of hours mowing lawns and g represents the number of hours planting gardens.

He can work a maximum of 40 hours per week, and would like to earn at least $250 this week.

Then, the system of the inequality becomes

m + g < 40

12m + 14g  > 250

3 0
3 years ago
Is that right? <br><br> Please help
kondaur [170]

Answer:

yes x = 16

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles, that is

133 = x + 117 ( subtract 117 from both sides )

16 = x

8 0
3 years ago
I need help ASAPPPPPPP!
telo118 [61]

Answer: The first box

Step-by-step explanation:

V represents volume and r represents radius

So V(r) represents the volume of the basketball with respect to radius

6 0
2 years ago
A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the
Naya [18.7K]

Answer:

The area is growing at a rate of \frac{dA}{dt} =226.2 \,\frac{cm^2}{min}

Step-by-step explanation:

<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>

We identify that the info given on the increasing rate of the circle's radius is 3 \frac{cm}{min} and we identify such as the following differential rate:

\frac{dr}{dt} = 3\,\frac{cm}{min}

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find  \frac{dA}{dt}.

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

A=\pi\,r^2

We now apply the derivative operator with respect to time (\frac{d}{dt}) to this equation, and use chain rule as we find the quadratic form of the radius:

\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}

Now we replace the known values of the rate at which the radius is growing ( \frac{dr}{dt} = 3\,\frac{cm}{min}), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\

which we can round to one decimal place as:

\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}

4 0
3 years ago
Which situation is modeled by the graph? the height of a jump rope being used over time the height of an elevator over time the
Sonbull [250]

A.) the height of a jump rope being used over time

8 0
3 years ago
Read 2 more answers
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