Question

What is the phase of y= -3cos (3x-pi) +5

Answer 1

Answer:

$- \frac{\pi}{3}$

Step-by-step explanation:

Given

$y = -3\cos(3x - \pi) + 5$

Required

The phase

We have:

$y = -3\cos(3x - \pi) + 5$

Rewrite as:

$y = -3\cos(3(x - \frac{\pi}{3})) + 5$

A cosine function is represented as:

$y = A\cos(B(x + C)) + D$

Where:

$C \to$ Phase

By comparison:

$C = - \frac{\pi}{3}$

Hence, the phase is: $- \frac{\pi}{3}$