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3 years ago

1/2 × 2 1/3 can u help

2 answers:

8 0

You are going to have to make 2 1/3 a improper fraction so how you do that is take 2×3=6+1=7 so it would be 7/3. 1/2×7/3=7/6 I think see if that works and if that don't help them flip 7/3 over because that is the reciprocal 3/7

lawyer [7]3 years ago

7 0

Thats easy its 7/6 hope this helps

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What is the domain of the function? <br>Function Wrap up review questions PLZ HELP

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2 years ago

What the equation of this graph?? I need help

yuradex [85]

X = 3

and

formula -

(y-y1)/(x-x1) = (y2-y1)/(x2-x1)

(x1,y1) = (4,1)
(x2,y2) =( 5,3)

(y-1)/(x-4) = (3-1)/(5-4)

y-1/x-4 = 2/1

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3 years ago

Help asap check picture

a_sh-v [17]

The remainder of the given expression will be 66.

<h3>What is division?</h3>

Division is a method of distributing a group of things into equal parts. It is one of the four basic operations of arithmetic.

The given polynomlal x⁴+3x³-6x²-12x-8 will be divided by x-3 so we need to find the remainder:-

x-3) x⁴+3x³-6x²-12x-8 ( x³-6x²+12x+24

x²-3x³

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6x³-6x²-12x-8

6x³-18x²

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12x²-12x-8

-12x²-36x

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Hence the remainder of the given expression will be 66.

To know more about division follow

brainly.com/question/25289437

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2 years ago

V144 = V121<br> What does this even mean

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Answer:

That equation doesn't make sense, so this equation means "no solution"

Step-by-step explanation:

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3 years ago

Read 2 more answers

Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos

crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c) $P(X = 2)$ is unusual, $P(X = 0)$ is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses $x$ is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

Two cans are randomly chosen, so $n = 2$

Two out of 18 cans are filled with diet coke, so $\pi = \frac{2}{18} = 0.11$

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121$

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921$

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that $P(X = 2)$ is unusual, since $P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05$

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958$

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0

4 years ago