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PIT_PIT [208]
3 years ago
8

To factor the quadratic expression x^2−8x−10 by completing the square, what value would be added? A. 64 B. 8 C. 16 D.-16

Mathematics
2 answers:
Elan Coil [88]3 years ago
4 0

Answer:

C

Step-by-step explanation:

When completing the square, we essentially want to create a perfect square trinomial by adding a constant.

If we have the following expression:

x^2+bx

And we want to complete the square, we will need to divide the b-coefficient by half and then square it.

Thus, the added term should be:

(b/2)^2

In the given equation, we have:

(x^2-8x)-10

The b term here is 8. Therefore:

(8/2)^2\\=(4)^2\\=16

The value we would add would be 16.

The answer is C.

Further notes:

To complete the square, add 16 like mentioned earlier. However, we also need to subtract 16 to balance things out:

(x^2-8x)-10\\=(x^2-8x+16)-10-16\\

The expression inside the parentheses is now a perfect square trinomial. Factor it:

=((x)^2-2(4)(x)+(4)^2)-26\\=(x-4)^2-26

And we are done!

levacccp [35]3 years ago
3 0

A quadratic function equation is as follows:

ax^{2}   +  bx + c

To complete the square, move the constant (c) to the other side of the equation and take half of the b value, square it, and add and subtract the same number.

In this problem, you will add 16.

\frac{ - 8}{2}  =  - 4

- 4^{2}  = 16

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2 years ago
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, two ind
liberstina [14]

Answer:

Step-by-step explanation:

Hello!

You have two populations of interest and want to compare them. If you define the study variables as:

X₁: average hourly wages of an employee of the Downtown store.

n₁= 25

X[bar]₁= $9

S₁= $2

X₂: average hourly wages of an employee of the North Mall store.

n₂= 20

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Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:

95% CI for μ₁ - μ₂

(X[bar]₁-X[bar]₂) ± t_{n_1+n_2-2; 1-\alpha /2} * (Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } )

Sa^2= \frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}

Sa^2= \frac{24*4+19*1}{25+20-2}= 2.67

Sa= 1.64

t_{n_1-n_2-2;1-\alpha /2} = t_{43; 0.975} = 2.017

(9-8)±2.017*(1.64*\sqrt{\frac{1}{25} +\frac{1}{20} } )

[0.007636;1.9923]

I hope it helps!

6 0
3 years ago
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