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zvonat [6]
3 years ago
6

Please help and explain how you got the correct answer!

Mathematics
1 answer:
Alexandra [31]3 years ago
3 0

Answer:

I am truly sorry, but all I see is Daniel the Tiger.

Step-by-step explanation:

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Prove the following DeMorgan's laws: if LaTeX: XX, LaTeX: AA and LaTeX: BB are sets and LaTeX: \{A_i: i\in I\} {Ai:i∈I} is a fam
MariettaO [177]
  • X-(A\cup B)=(X-A)\cap(X-B)

I'll assume the usual definition of set difference, X-A=\{x\in X,x\not\in A\}.

Let x\in X-(A\cup B). Then x\in X and x\not\in(A\cup B). If x\not\in(A\cup B), then x\not\in A and x\not\in B. This means x\in X,x\not\in A and x\in X,x\not\in B, so it follows that x\in(X-A)\cap(X-B). Hence X-(A\cup B)\subset(X-A)\cap(X-B).

Now let x\in(X-A)\cap(X-B). Then x\in X-A and x\in X-B. By definition of set difference, x\in X,x\not\in A and x\in X,x\not\in B. Since x\not A,x\not\in B, we have x\not\in(A\cup B), and so x\in X-(A\cup B). Hence (X-A)\cap(X-B)\subset X-(A\cup B).

The two sets are subsets of one another, so they must be equal.

  • X-\left(\bigcup\limits_{i\in I}A_i\right)=\bigcap\limits_{i\in I}(X-A_i)

The proof of this is the same as above, you just have to indicate that membership, of lack thereof, holds for all indices i\in I.

Proof of one direction for example:

Let x\in X-\left(\bigcup\limits_{i\in I}A_i\right). Then x\in X and x\not\in\bigcup\limits_{i\in I}A_i, which in turn means x\not\in A_i for all i\in I. This means x\in X,x\not\in A_{i_1}, and x\in X,x\not\in A_{i_2}, and so on, where \{i_1,i_2,\ldots\}\subset I, for all i\in I. This means x\in X-A_{i_1}, and x\in X-A_{i_2}, and so on, so x\in\bigcap\limits_{i\in I}(X-A_i). Hence X-\left(\bigcup\limits_{i\in I}A_i\right)\subset\bigcap\limits_{i\in I}(X-A_i).

4 0
3 years ago
PLEASE help me with this question! This is really urgent! No nonsense answers please.
algol [13]

Answer:

The last answer choice: Jalon can score 10 times as many points in the next level as in the level he has reached.

Step-by-step explanation:

For every level increase the number of points is multiplied by 10.  So after reaching the first level, Jalon will have 10 points.  After the second level, 100 points.  After the thierd level, 1000 points.  After the fourth level, 10000 points, and so on like that.

5 0
3 years ago
Find the x - intercept of the graph of the equation
Alborosie

Answer:

ugh should i drop out

Step-by-step explanation:

5 0
3 years ago
5x88x9x7x3x9x10x31x47=
Gre4nikov [31]
1.09047708 E10 i guess
6 0
3 years ago
Read 2 more answers
The school auditorium has 900 seats. The inequality, with x representing adults and y representing children, can be solved to fi
Paha777 [63]

Answer:

Step-by-step explanation:

The ordered pair is located on the boundary line of the graph of the inequality, and because the sign is "less than or equal to", the values on the boundary line are also included in the solution set.

Looking at this logically, we also see that it certainly possible for half the seats to be occupied by adults and half by children.

5 0
3 years ago
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