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Murljashka [212]
2 years ago
15

Translate the point (5,2)—> 3 units to the left

Mathematics
1 answer:
VladimirAG [237]2 years ago
7 0

Given:

The point (5,-2) is translated 3 units to the left.

To find:

The new location of the point.

Solution:

If a point is translated 3 units to the left, then

(x,y)\to (x-3,y)

Using this rule of translation, we get

(5,-2)\to (5-3,-2)

(5,-2)\to (2,-2)

Therefore, the new location of the point is (2,-2). Hence, the correct option is C.

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3 0
3 years ago
How to solve for 6x-12+2x=3+8x-15
Alecsey [184]
6x−12+2x=3+8x−15

Simplify:

6x+−12+2x=3+8x+−15

(6x+2x)+(−12)=(8x)+(3+−15)(Combine Like Terms)

8x+−12=8x+−12


8x−12=8x−12

Subtract 8x from both sides.

8x−12−8x=8x−12−8x

−12=−12

Add 12 to both sides.

−12+12=−12+12

0=0

The real numbers are the only solution we can have.


4 0
3 years ago
Round of 38828 to the nearest 10​
RUDIKE [14]

Step-by-step explanation:

We're going to be evaluating if we can round 2. (Values in the 10's place)


The value in the 'ones' place has to be greater than or equal to 5
in order to round up 2.

Since 8 is greater than 5, we can round up 2.

<u>Rounded answer:</u>

38830

5 0
2 years ago
Find a polynomial function of degree 4 with − 2 as a zero of multiplicity 3 and 0 as a zero of multiplicity 1.
MArishka [77]
Degree 4 means you'll have x^4 as your leading term. Multiplicity of 3 means you have the same factor 3 times. So if x = -2, then (x + 2) = 0, so (x + 2) is used 3 times. FOIL that out 3 times and you get x^3 + 6x^2 + 12x + 8. Now multiply by (x + 0) to get a 4th degree polynomial of x^4 + 6x^3 + 12x^2 + 8x. There!
3 0
3 years ago
What are the values of a, and r of the geometric series?
Charra [1.4K]
A. A= ray and r=2
That’s the answer
7 0
2 years ago
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