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mote1985 [20]
3 years ago
13

Why do organisms need water, food, air, and living space

Chemistry
1 answer:
xxTIMURxx [149]3 years ago
7 0
Living things need air, food, and water because they are essential to the chemical processes that provide organisms with energy and keep them alive.
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Where are elements with atomic numbers 1 and 2?
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Answer:hydrogen(H) is 1  and helium(He) is 2

hydrogen is a nonmetal and helium is a nobel gas. hydrogen is found in group S and helium is found in group P

Explanation:hope this helps

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Which statement about Schrödinger's theory of the atomic model is true?
vekshin1

Answer : Option C) It explained the odds of finding the position of an electron.

Explanation : Schrödinger's theory of the atomic model is true for the probability of finding the electron around the nucleus. Schrödinger used odd mathematical equations to describe the likelihood of finding an electron in a certain position around the nucleus. This atomic model was known as the quantum mechanical model of the atom. He posed an equation which is now called as the Schordinger’s Wave Equation, which incorporates both the wave-like and particle-like behaviors of electrons, which stated that electrons can act like waves/light and particles. Which later helped to develop the uncertainty principle for finding the probable position of the electron.

4 0
4 years ago
I’ll give brainliest to whoever is right
Vlad1618 [11]
Nucleolus should be it
7 0
3 years ago
How many grams of Cl are in 535 g of CaCl₂?
Sliva [168]
The answer is 341.7 g.

(1) Calculate the molar mass (M) of CaCl2 which is the sum of atomic masses (A) of elements:
M(CaCl2) = A(Ca) + 2A(Cl)
A(Ca) = 40.1 g/mol
A(Cl) = 35.45 g/mol

M(CaCl2) = 40.1 + 2 * 35.45 = 40.1 + 70.9 = 111 g/mol

(2) Calculate in how many moles are 535 g:
M(CaCl2) = 111 g/mol
111g : 1mol = 535 g : xmol
x = 535 g * 1mol : 111g = 4.82 mol

(3) Calculate how many grams of Cl are in 4.82 mol:
A(Cl) = 35.45 g/mol 
2A(Cl) = 2 * 35.45 = 70.9 g/mol
70.9 g : 1 mol = x : 4.82 mol
x = 70.9 g * 4.82 mol : 1 mol = 341.7 g
7 0
3 years ago
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