Answer:
C
Explanation:
It afffects changes in pressure and temperature not melting and boiling points
Answer:
Samarium
Explanation:
The element Sm describe is called Samarium. This element has unique sets of properties that makes it very unique and distinct.
The lanthanides are found in the f-block on the periodic table of elements.
This element is a moderately hard silvery metal that readily oxidizes in air. It assumes an oxidation state of +3. The element has an atomic number of 62
Anion is an atom with a negative charge
so in this case it woulld be O2-
C-Cl bond is polar.
As Cl is more electronegative than C,
Cl pulls the shared electrons towards its side making the C-Cl bond polar.
Polar meaning C gets a partial positive charge and Cl gets a partial negative charge. Thus C-Cl bond becomes polar.
CCl4 molecule is tetrahedral.
And its shape is symmetrical.
That means its similar on all corners or all planes and it can be cut into equal halves from any plane.
C-Cl bond is polar.But the C-Cl polairty gets cancelled out as its pulled equally from all sides.
Since the molecule is symmetrical CCl4 is non polar.
F. <em>None of the above
</em>
<em>No O atoms are present</em> as reacting substances, only O_2 and H_2O molecules.
O_2 + 2H_2O + 2e^(-) → 4OH^(-)
We must use <em>oxidation numbers</em> to decide whether oxygen or water is the substance reduced.
The oxidation number of O changes from 0 in O_2 to -2 in OH^(-).
A decrease in oxidation number is <em>reduction</em>, so O_2 is the substance reduced.
The oxidation number of O is -2 in both H_2O and OH^(-), so water is <em>neither oxidized nor reduced</em>.
