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storchak [24]
3 years ago
15

The data set gives the number of hours it took each of the 10 students in a cooking class to master a particular technique.

Mathematics
2 answers:
meriva3 years ago
7 0

Answer:   The best measure of center for this data set is <u>median</u> , and its value is <u>4.5</u> .

Step-by-step explanation:

The given data set : {5, 3, 5, 30, 4, 5, 4, 3, 4, 5}

We can see that it has an outlier (i.e. 30) which is extremely large from all the values.

We know that to measure the center of tendency we measure one of three things arranged in ascending order:

Mode< Median <Mean

But mean gets affected by outlier value.

Then the best measure of center for this data set must be Median.

For this, arrange given data set in order:

{3 ,3 ,4 ,4 ,4 ,5 ,5 ,5 ,5 ,30 }

Since , the number of data values = 10 (even)

Then , Median = Mean of two middle most numbers

\dfrac{4+5}{2}=4.5

Hence, the best measure of center for this data set is <u>median</u> , and its value is <u>4.5</u> .

iris [78.8K]3 years ago
4 0
4.5 thats the answer. Im just typing so its long enough blah blah blah

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In this diagram, BAC~EDF. If the area of BAC=15 in2, what is the area of EDF? 4, 5.
lesya692 [45]

Answer:

9.6 square inches.

Step-by-step explanation:

We are given that ΔBAC is similar to ΔEDF, and that the area of ΔBAC is 15 inches. And we want to determine the area of ΔDEF.

First, find the scale factor <em>k</em> from ΔBAC to ΔDEF:

\displaystyle 5 k = 4

Solve for the scale factor <em>k: </em>

<em />\displaystyle k = \frac{4}{5}<em />

<em />

Recall that to scale areas, we square the scale factor.

In other words, since the scale factor for sides from ΔBAC to ΔDEF is 4/5, the scale factor for its area will be (4/5)² or 16/25.

Hence, the area of ΔEDF is:

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In conclusion, the area of ΔEDF is 9.6 square inches.

5 0
3 years ago
What role do animals have in the carbon cycle?
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4 0
2 years ago
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Simplify the following expression.<br> log(9x^5) + 5 log (1/x)
Darya [45]

Answer:

log9

Step-by-step explanation:

hello :

note :  a>0 and b>0

1) log(ab) = loga+logb

2) loga^n = nloga.....n in N

log(9x^5) + 5 log (1/x) = log(9x^5) +  log (1/x)^5 = log((9x^5) (1/x)^5)

                                 = log(9x^5)/(x^5)) = log9  because : (1/x)^5 = 1/x^5

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Andreyy89

Answer:

y=(1/3)x-2

Step-by-step explanation:

Plug into equation of y=mx+b

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