The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>The equation of the function is given as:
Expand the function
Reorder the terms
Factor the expression
Factor out x -1
Expand
Factorize
Factor out x + 2
The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
Read more about functions at:
#SPJ1