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beks73 [17]
3 years ago
12

Please I need help with this question!!

Mathematics
2 answers:
KIM [24]3 years ago
7 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{6 \frac{1}{12} \:  \:  \: inches}}}}}

Step-by-step explanation:

Total inches of a green ribbon = \sf{15 \frac{1}{2} }

<u>Finding</u><u> </u><u>the</u><u> </u><u>total </u><u>inches</u><u> </u><u>of </u><u>ribbon</u><u> </u><u>that</u><u> </u><u>she</u><u> </u><u>cut</u><u> </u><u>off</u>

\sf{2 \frac{3}{4}  + 6 \frac{2}{3} }

Convert the mixed number into an improper fraction

\dashrightarrow{ \sf{ \frac{2 \times 4 + 3}{4}  +  \frac{3 \times 6 + 2}{3}}}

\dashrightarrow{ \sf{ \frac{8 + 3}{4} +  \frac{18 + 2}{3} }}

\dashrightarrow{ \sf{ \frac{11}{4}  +  \frac{20}{3} }}

Take the L.C.M ( Least Common Multiple ) of 4 and 3

L.C.M = 4 and 3 = 12

\dashrightarrow{ \sf{ \frac{11 \times 3 + 20  \times 4}{12} }}

\dashrightarrow{ \sf{ \frac{33 + 80}{12}}}

\dashrightarrow{ \sf{ \frac{113}{12} }}

Total inches of ribbon that she cut off = 113/12

<u>Now</u><u>,</u><u> </u><u>finding </u><u>the</u><u> </u><u>left</u><u> </u><u>inches</u><u> </u><u>of</u><u> </u><u>ribbon</u>

\sf{15 \frac{1}{2}  -  \frac{113}{12} }

Convert mixed number into improper fraction

\dashrightarrow{ \sf{ \frac{15 \times 2 + 1}{2}   -   \frac{113}{12} }}

\dashrightarrow {\sf{ \frac{31}{2}   -   \frac{113}{12} }}

Take the L.C.M of 2 and 12 , you will get 12

\dashrightarrow{ \sf{ \frac{31 \times 6  - 113}{2} }}

\dashrightarrow{ \sf{ \frac{186  -  113}{12}}}

\dashrightarrow{ \sf{ \frac{73}{12} }}

Convert the improper fraction into mixed number

\dashrightarrow{ \sf{6 \frac{1}{12} }} inches

Hope I helped!

Best regards! :D

nalin [4]3 years ago
5 0

[15 + 1/2 ] - [ 2 + 3/4 ] - [6 + 2/3 ]......convertng these to improper fractions, we have

[31 /2 ] - [11 / 4 ] - [ 20 / 3 ] getting a common denominator (12), we have

[186 / 12] - [33 / 12 ] - [ 80 / 12 ] = 73 / 12 inches = about 6.0833 inches left

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<u>Solution:</u>

Given that, the ratio of the angles of a triangle is 5: \frac{2}{3}: 1

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Answer:

Range = 60-5=55

In order to find the variance and deviation we need to find the mean with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X =36.07

Now we can find the variance with the following formula:

s^2 =\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

And replacing we got:

s^2=357.610

And the standard deviation would be:

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For this case since the range observed is large is better to use a measure of variation in order to check the spread of the values and take a decision useful

Step-by-step explanation:

For this case we have the following dataset:

60 58 55 53 47 45 44 43 25 25 20 18 7 5

We can find the range with this formula:

Range = Max-Min

And replacing we got:

Range = 60-5=55

In order to find the variance and deviation we need to find the mean with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X =36.07

Now we can find the variance with the following formula:

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And replacing we got:

s^2=357.610

And the standard deviation would be:

s = \sqrt{357.610}= 18.911

For this case since the range observed is large is better to use a measure of variation in order to check the spread of the values and take a decision useful

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