"Volume(10) = 1,000" and "Volume(2) = 8" are the two statements among the following choices given in the question that is true. The correct options among all the options that are given in the question are option "B" and option "C". I hope that this is the answer that has actually come to your great help.
Answer:
y = 25h + 50
Step-by-step explanation:
Let's say he stayed for two hours.
y = 25(2) + 50
y = 50 + 50
y = 100
Question 1:
To start off this question, we can tell that this is a square because it has 4 right angles and 4 congruent sides.
A square has four parallel sides and 4 congruent sides, so a square is a rhombus and parallelogram.
A square has 4 right angles, so it's also a rectangle.
A square has 4 sides, so it's also a quadrilateral.
The first choice is your answer.
Question 2:
Not all quadrilaterals are rectangles, so A is incorrect.
Not all quadrilaterals are squares, so B is incorrect.
All rectangles are types of quadrilaterals, so C is correct.
Not all quadrilaterals are parallelograms, so D is incorrect.
Thus, C is your answer.
Question 3:
The first choice will not work because a rhombus will satisfy those conditions, and a rhombus is not always a square.
The second choice will work because only a square will satisfy that condition because only squares have 4 congruent sides along with equal diagonals.
Thus, the second choice is your answer.
Have an awesome day! :)
-30 is the answer
-6+4(-6)
-6+(-24)
-30
Answer:
21 consonant tiles
Step-by-step explanation:
Henry has a bag containing 39 letter tiles, some consonants, and some vowels.
He selects a tile without looking and then replaces it. If he pulls 7 consonant tiles and 6 vowel tiles, which is the most likely number of consonant tiles in Henry's bag?
Step 1
We add up the number of tiles that he pulls out of the bag
= 7 consonant tiles + 6 vowel tiles
= 13 tiles
Step 2
We divide the total number of tiles in the bag by the total number of tiles that was pulled out of the bag
= 39 tiles ÷ 13 tiles
= 3
Step 3
The most likely number of consonant tiles in Henry's bag is calculated as:
3 × The number of consonant tiles that was pulled out of the bag.
Hence:
3 × 7 consonant tiles
= 21 consonant tiles.
Therefore, the most likely number of consonant tiles in Henry's bag is 21 consonant tiles.
