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Shkiper50 [21]
3 years ago
9

Chloe received 86% on her first test, a 47/50 in her next test, and a 0.89 on her third test. List her percentages in order from

least to greatest.
Mathematics
1 answer:
Mumz [18]3 years ago
7 0

Answer:

  84%, 86%, 89%

Step-by-step explanation:

The three numbers, expressed as percentages, are ...

  • 86%
  • (47/50)×100% = 84%
  • 0.89×100% = 89%

Smallest to largest, they are 84%, 86%, and 89%. In the original form, they are 47/50, 86%, and 0.89.

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PLEASE HELP!! I WILL MARK THE FIRST CORRECT ANSWER BRAINLIEST!!))What is the volume of this cylinder?
Aleksandr-060686 [28]

Answer:

V = 6079.04 ft³

Step-by-step explanation:

The volume (V) of a cylinder is calculated as

V = πr²h ( r is the radius and h the height )

Here diameter = 22 , then r = 22 ÷ 2 = 11 and h = 16 , then

V = 3.14 × 11² × 16

   = 3.14 × 121 × 16

  ≈ 6079.04 ft³ ( to the nearest hundredth )

6 0
2 years ago
Sarah has $55.00 to spend
GenaCL600 [577]
The equation that models the relationship between the amount of money Sarah has left is 55- 0.65x= y
8 0
3 years ago
The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti
melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that m = 100, \mu = \frac{1}{100} = 0.01

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

P(X > x) = e^{-\mu x}

This is P(X > 190). So

P(X > 190) = e^{-0.01*190} = 0.1496

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

P(X > x) = 0.08

So

e^{-0.01x} = 0.08

\ln{e^{-0.01x}} = \ln{0.08}

-0.01x = \ln{0.08}

x = -\frac{\ln{0.08}}{0.01}

x = 252.6

Capacity of 252.6 cubic feet per second

5 0
3 years ago
A restaurant sells about 330 sandwiches each day at a price of $6 each $.25 decrease in price. 15 more sandwiches are sold per d
zmey [24]

Answer:

restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

Step-by-step explanation:

to calculate current revenue= $6 x 330 = $1980

suppose x as the number of times the price to be dropped by $0.25

then find new price.. i.e

new price= $(6-0.25x)

and, new sell=330 +15x sandwiches

therefore, the new revenue would be= (6-0.25x)(330 +15x)

in order to maximize the current revenue, simplify the above equation and make it complete square using x

(6-0.25x)(330 +15x)

=1980-82.5x +90x -3.75x^{2}

=1980 + 7.5x -3.75x^{2}

=1980-3.75 (-2x+x^{2}) ----> taking out common

now, to make a complete square lets add and subtract 1 inside the parentheses

=1980-3.75(-1+1-2x+x^{2})

=1980 +3.75 -3.75(x^{2} -2x +1)

=1983.75 -3.75 (x-1)^{2}---->(1)

as (x-1)^{2} is positive always, minimize the other term in order to maximize the total revenue.

so the minimum possible value of (x-1)^{2} = 0

therefore, x=1

putting x in eq(1) the revenure becomes,

$(1983.75-0)=> $1983.75

therefore, restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

3 0
3 years ago
Write an equation in slope-Intercept form for the line with slope 2/5 and y- ntercept - 3 .
Trava [24]

Answer:

y = \frac{2}{5} x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = \frac{2}{5} and c = - 3 , then

y = \frac{2}{5} x - 3 ← equation of line

7 0
3 years ago
Read 2 more answers
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