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Mandarinka [93]
3 years ago
6

The line ab has midpoint (-2, 4) a has coordinates (3, -2) find the coordinates of b

Mathematics
1 answer:
damaskus [11]3 years ago
6 0

Answer:

b = (- 7, 10 )

Step-by-step explanation:

Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ \frac{1}{2} (x₁ + x₂ ), \frac{1}{2} (y₁ + y₂ ) ]

let the coordinates of b = (x, y ) then use the formula and equate to the coordinates of the midpoint, that is

\frac{1}{2} (x + 3) = - 2 ( multiply both sides by 2 )

x + 3 = - 4 ( subtract 3 from both sides )

x = - 7

\frac{1}{2} (y - 2) = 4 ( multiply both sides by 2 )

y - 2 = 8 ( add 2 to both sides )

y = 10

Thus the coordinates of b are (- 7, 10 )

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Answer:

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Step-by-step explanation:

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3 years ago
PLEASE HELP!!!
vovikov84 [41]

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Part A

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This, when applied to our case becomes, "The length of the secant RT, times its external segment, ST, equals the square of the tangent segment TU".

Mathematically, it can be written as:

Part B

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