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3 years ago

If we reject the null hypothesis, h0: ρ = 0 , what can we conclude about the population correlation coefficient?

1 answer:

5 0

If the null hypothesis, $H_0:\:\rho =0$ is rejected, then we can conclude that the correlation coefficient is significant. This means that there is enough evidence to conclude that a relationship exists between the two (or more) variables involved in the regression.

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What is the answer to mr. House wrote 8tenths minus 5 hundredths on the board.Maggie said the answer is 3 hundredths because 8 m

kicyunya [14]

No ou are wrong because 8 tenths = 80 while 5 hundredths= 500 the right answer is gonna be 80-500= -420

4 0

3 years ago

In a school presidential race, Jeb received 100 votes, Janine 60, and Arnie 40 votes. Make a circle graph to display the data as

Anarel [89]

Answer:

Jeb: 50%, Janine: 30%, Arnie: 20%

Step-by-step explanation:

100+60+40=

200 votes in total

1% of 200 = 2

100 divided by 2 = 50

60 divided by 2 = 30

40 divided by 2 = 20

Hope this helps!

7 0

3 years ago

Read 2 more answers

Which pair shows equivalent expressions?

Dmitry_Shevchenko [17]

Which pair shows equivalent expressions?

A.2(2/5x + 2)=2 2/5x + 1

B.2(2/5x + 2)=4/5x + 4

C.2(2/5x + 4)=4/5x + 2

D.2(2/5x + 4)=2 2/5x + 8

Solution:

$2(\frac{2}{5}x + 2)$

Let us distribute 2 inside the parenthesis.

That is, we use distributive property:

a(b+c)=ab+ac

$2(\frac{2}{5}x + 2) =\frac{2*2}{5}x+2*2$

So, $2(\frac{2}{5}x + 2) =\frac{4}{5}x+4$

Answer:Option (b)

$2(\frac{2}{5}x+4)$

Applying distributive property, a(b+c)=ab+ac

$2(\frac{2}{5}x+4) =2*\frac{2}{5} x+2*4$

$2(\frac{2}{5}x+4) =\frac{2*2}{5} x+2*4$

$2(\frac{2}{5}x+4) =\frac{4}{5} x+8$

So, Option (B) is correct.

8 0

3 years ago

Read 2 more answers

Answer this question to get marked as brainliest!!!!!

____ [38]

Answer:

Step-by-step explanation:

3 0

2 years ago

A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$

Then, we can calculate the standard error of the mean as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5$

6 0

3 years ago