Answer:
The area of the rectangle is increasing at a rate of 84 square centimeters per second.
Step-by-step explanation:
The area for a rectangle is given by the formula:

Where <em>w</em> is the width and <em>l</em> is the length.
We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.
First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>
![\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BdA%7D%7Bdt%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%5Bw%5Cell%5D)
By the Product Rule:

Since we know that dl/dt = 6 and that dw/dt = 5:

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.
Answer:
The linear equation in two variables is 5u - 8v = 150 .
Step-by-step explanation:
As given
The cost of 5 tables exceeds the cost of 8 chairs by Rs150 .
Let us assume that the cost of one table be u .
Let us assume that the cost of one chairs be v .
Than the equation becomes
5u + 150 = 8v
Simplify the above equation
5u - 8v = 150
Therefore the linear equation in two variables is 5u - 8v = 150 .
Answer:
p=4CP - 26
C= p/4P + 13/2P
P= P/4C +13/2C
Step-by-step explanation:
Answer:
I guess! I will try my best! I may not know all the answers, but I can help you with most I hope!
I hope that works?
Step-by-step explanation:
Would this work? Hope it helps