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Margarita [4]
3 years ago
11

15 POINTS! someone pls answer

Mathematics
1 answer:
photoshop1234 [79]3 years ago
5 0

Answer:

2(\frac{1}{2} *20*50)+2(\frac{1}{2} *20*10)

Step-by-step explanation:

The formula for the area of a triangle is \frac{1}{2} *b*h

The triangles that can be made is the triangle that has legs 20 and 50 and the triangle that has legs 20 and 10.

Since there are 2 of each triangles, we get:

2(\frac{1}{2} *20*50)+2(\frac{1}{2} *20*10)

The answer that fits is the first option.

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Find the projection of u = <–6, –7> onto v = <1, 1> a. <-13/2,-13/2> b. <39,91/2> c. <-13/1764,-13/17
Alexandra [31]
<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

proj_vu = (\frac{u.v}{|v|^2})v               ----------------(i)

Where;

u.v is the dot product of vectors u and v

|v| is the magnitude of vector v

Given:

u = <-6, -7>

v = <1, 1>

These can be re-written in unit vector notation as;

u = -6i -7j

v = i + j

<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

u . v = (-6i - 7j) . (i + j)

u . v = (-6i) (1i) + (-7j)(1j)          [Remember that, i.i = j.j = 1]

u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

|v| = \sqrt{2}

<em>Substitute these values into equation (i) as follows;</em>

proj_vu = [\frac{-13}{(\sqrt{2}) ^2}][i + j]

proj_vu = \frac{-13}{2} [i + j]

This can be re-written as;

proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

proj_vu =

5 0
3 years ago
If you flip a coin and roll a 6-sided die, what is the probability that you will flip a tails and roll more than a 3?
pishuonlain [190]
Prob of tails times prob of rolling more than 3
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Check the picture below.

make sure your calculator is in Degree mode.

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A midpoint of a segment is a point that divides the segment into two congruent
myrzilka [38]

Answer:

True

Step-by-step explanation:

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Describe how the graph of y=2x and y=2x+7 are the same.​
MaRussiya [10]

Answer:

These two equations produce a similar graph because they both share the same slope: 2. The only difference is that the y-intercept for the second equation is a positive 7, making the graph shift upwards. Other than this, both equations would be parallel (and identical) on the graph.

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