Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Gosh, when I saw that my mind went blank
Hello hello helllo hello hello hello
9x⁹ - 90x⁸ - 351x⁷
What do each of these numbers have in common?
They ALL have 9x⁷ in them!
So, divide each one of these by 9x⁷
9x⁹ ÷ 9x⁷ = 9x²
-90x⁸ ÷ 9x⁷ = -9x
-351x⁷ ÷ 9x⁷ = -39
So, factorized completely, it is :
9x² - 9x - 39
~Hope I helped!~
The answer should be b¹². You add the exponents of each constant. In the case of the simple b the exponent would be one.
