X=-2→y=7(6)^(-2+2)+1=7(6)^0+1=7(1)+1=7+1→y=8; (x,y)=(-2,8)
x=-5→y=7(6)^(-5+2)+1=7(6)^(-3)+1=7/6^3+1=7/216+1=0.0324+1→y=1.0324→(x,y)=(-5,1.0324)
Answer: Graph 3
Answer:
2.5 cm
Step-by-step explanation:
Rectangle A L x W = 40
Rectangle B L * W = 1/2 (40)
8 * W = 20
W = 2.5 cm
Answer:
y = 2/3x + 4
Step-by-step explanation:
First, we look at where the equation intersects the y axis. It intersects at y = 4, which means that in the end of the equation there must be a "+4", so we can rule out the first two.
Second, we look at the slope of the line. Slope is defined as rise over run. As you can see in the graph, the line moves up 2 units while moving right 3 units. That means the coefficient of x (which is the slope) will be 2/3, which means the answer is y = 2/3x + 4.
n=3; We need a third degree polynomials with the following given zero's: 2 and 5i are zeros; f(-1)=156.
Since these are solutions
x = 2 ; x = 5i. Since imaginaries travel in pairs, the other answer is x= -5i.
We have (x-2)(x-5i)(x+5i) = 0
Now,
f(-1) = (-1-2)(-1-5i)(-1+5i) = 156.
f(-1) = (-3)(26) = -78.
But -78 x -2 = 156, so our polynomial becomes
Y= -2x (<em>x</em> - 2 ) x (<em>x </em>to the power of 2 + 25) = 0
Answer: the cost of an adult ticket is $9.
The cost of a child's ticket is $13
Step-by-step explanation:
Let x represent the price of one adult ticket.
Let y represent the price of one student ticket.
On the first day of ticket sales, the school sold two adult tickets and three students tickets for a total of $57. It means that
2x + 3y = 57- - - - - - - - - -1
The school took and $70 on the second day by selling two adult tickets and four student tickets. It means that
2x + 4y = 70- - - - - - - - - -2
Subtracting equation 2 from equation 1, it becomes
- y = - 13
y = 13
Substituting y = 13 into equation 1, it becomes
2x + 3 × 13 = 57
2x + 39 = 57
2x = 57 - 39 = 18
x = 18/2
x = 9
