I need a 5 digital number
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The mean exists at 3 and the standard deviation exists 0.87.
Using the binomial distribution, it exists seen that the mean and the standard deviation of X exist given as follows:
The expected value of the binomial distribution exists:
The standard deviation of the binomial distribution exists:
In this problem, the proportion and the sample size exist given as follows:
p = 0.75
n = 4
Therefore, the mean and the standard deviation exist given by:
The mean exists at 3 and the standard deviation exists 0.87.
To learn about the binomial distribution refer to:
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