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enot [183]
2 years ago
8

Sameer chose 12 different toppings for his frozen yogurt sundae, which was Three-fourths of the total number of different toppin

gs available at the make-your-own sundae shop. To determine the number of different toppings available at the shop, Sameer set up and solved the equation as shown below.
Three-fourths = StartFraction x over 12 EndFraction. Three-fourths (12) = StartFraction x over 12 EndFraction (12). 9 = x.
?
Mathematics
2 answers:
stich3 [128]2 years ago
7 0

Answer: B

Step-by-step explanation:

34kurt2 years ago
6 0

Answer:

2/56

Step-by-step explanation:

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Can someone help me with this problem please. ( I need it as fast as possible).
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D-B-A-C

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Write y=−4x−3 in standard form . ( I'LL MARK BRAINLIEST)
choli [55]

Answer:

4 x + y = − 3

Step-by-step explanation:

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2 years ago
You are fixing the roof of your house when a hammer breaks loose and slides down. the roof makes an angle of 65
olga_2 [115]
The angle would be 5,000m
6 0
3 years ago
Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

where \mathcal C is the circular boundary of the hemisphere \mathcal M in the y-z plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

where 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi

We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

and we can parameterize \mathcal M by

\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle

so that

\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

where 0\le v\le\dfrac\pi2 and 0\le u\le2\pi. Then,

\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

as expected.
7 0
3 years ago
What is (4a²)³÷8a²? can you please answer in normal number form (not like 3²)
AleksandrR [38]

Answer:

8a^4

Step-by-step explanation:

Hello! (4a^2)^3=4\cdot4\cdot4\cdot a^2\cdot a^2\cdot a^2=64a^6because if you multiply numbers with exponents you add the exponents.

Now we've got\frac{64a^6}{8a^2}=8a^4.

Sadly it has to be in exponential form. You can substitute a into the equation if you know a.

3 0
3 years ago
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