3x(5x+6)-8(1+8x)
15x^2+18x-8-64x
15x^2-46x-8 is your final answer
Answer:
Correct answer: x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3
Step-by-step explanation:
Given:
3 x⁴ + 14 x² - 5 = 0 biquadratic equation
this equation is solved by a shift x² = t and get:
3 t² + 14 t - 5 = 0
t₁₂ = (-14 ± √14² - 4 · 3 · 5) / 2 · 3 = (-14 ± √196 + 60) / 6
t₁₂ = (-14 ± √256) / 6 = (-14 ± 16) / 6
t₁ = -5 or t₂ = 1 / 3
the solution t₁ = -5 is not accepted because it cannot be x² = -5
we accepted t₂ = 1 / 3
x² = 1 / 3 ⇒
x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3
God is with you!!!
The anwser is
4/5x = 16
5/4 x(multiply) 4/5x = 5/4x 16
X= 5x(multiply)4
X=20
(Not 100% sure about the work but the anwser is right)
Answer:
11
Step-by-step explanation:
W^7/W^-2=W^7+2=W^9 ( when divide subtract the exponent (7-(-2))
W^?/W² = W^?-2
W^9=W^(?-2)
9=?-2
?=11
W^7/W^-2 = W^11/W²
