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JulijaS [17]
3 years ago
15

What is 6/6 equivalent to

Mathematics
2 answers:
Naddika [18.5K]3 years ago
3 0

Answer:

1 whole

Step-by-step explanation:

Sveta_85 [38]3 years ago
3 0

Answer:1

Step-by-step explanation:You have 6 sixths. That means it is a whole number

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What is the angle of C?
soldier1979 [14.2K]

Answer:

50°

Step-by-step explanation:

65 + 65 +C = 180

130+C = 180

C = 180 - 130 = 50

3 0
3 years ago
Read 2 more answers
Which is the equation in slope-intercept form for the line that passes through (3, 7) and is perpendicular to 3x-5y=8
Natalija [7]

Answer:

C

Step-by-step explanation:

Perpendicular lines have slopes which are the negative reciprocal of each other. To find the slope, convert 3x-5y=8 into y=mx+b form.

3x-5y=8

-5y = -3x +8

y = 3/5 x - 8/5

The slope is 3/5 so its perpendicular slope is -5/3. Write the equation of this line through the point (3,7) using point slope form. Then simplify into y=mx+b form.

y-y_1=m(x-x_1)\\y-7 = -\frac{5}{3}(x-3)\\y-7=-\frac{5}{3}x + 5\\y = -\frac{5}{3}x+12

5 0
3 years ago
Which action will solve the equation?. m + 20 = 9. . Add 9 to each side.. Subtract 9 from each side.. Add 20 to each side.. Subt
Kruka [31]
M + 20 = 9
u need to subtract 20 from both sides because u want to isolate m

m + 20 = 9
m + 20 - 20 = 9 - 20
m = - 11
4 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (-5,2 ) and has the slope of -2/5
valina [46]

Answer:

y = -2/5x + 2

Step-by-step explanation:

8 0
2 years ago
The level of nitrogen oxides (nox) in the exhaust after 50,000 miles or fewer of driving of cars of a particular model varies no
mina [271]
<span>Answer: 0.533</span>

Explanation: Note that

x \ \textgreater \ I \\ \Leftrightarrow x - 0.3 \ \textgreater \ I - 0.3 \\ \\ \Leftrightarrow \boxed{\frac{x - 0.3}{0.1} \ \textgreater \ \frac{I - 0.3}{0.1}} (1) 

Let

z_1 = z-score for I.
z_2 = z-score for x. 

The formula for z-score is given by

\text{z-score} = \frac{(\text{data point}) - (\text{mean})}{(\text{standard deviation})}

So,

z_2 = \frac{x - 0.3}{0.1}

z_1 = \frac{I - 0.3}{0.1}

Based on inequality in (1), 

z_2 > \  z_1 

So, 

P(x \ \textgreater \  I) = 0.01&#10;\\&#10;\\ \Leftrightarrow P \left (\frac{x - 0.3}{0.1} \ \textgreater \ \frac{I - 0.3}{0.1}  \right ) = 0.01 &#10;\\&#10;\\ \Leftrightarrow P(z_2 \ \textgreater \  z_1) = 0.01&#10;\\&#10;\\ \Leftrightarrow 1 - P(z_2 \leq z_1) = 0.01&#10;\\&#10;\\ \Leftrightarrow \boxed{P(z_2 \leq z_1) = 0.99}

Since z_1 and z_2 are z-scores and the level of nitrogen oxides are normally distributed, using normal distribution calculator (or table), 

z_1 = 2.326&#10;\\&#10;\\ \Leftrightarrow \frac{I - 0.3}{0.1} = 2.326&#10;\\&#10;\\ \Leftrightarrow I - 0.3 = 0.1(2.326)&#10;\\&#10;\\ \Leftrightarrow I - 0.03 = 0.2326&#10;\\&#10;\\ \Leftrightarrow \boxed{I \approx 0.533}



4 0
3 years ago
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