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2 years ago

I need help with this one.

Mathematics

1 answer:

Elanso [62]2 years ago

3 0

Answer:

y=(-4/1)x-5

Step-by-step explanation:

You need to find the slope of the line and the y intercept, you can do this by plotting the points into a graph and figuring it out that way, or you can use the equations y2-y1/x2-x1 (for slope) and y=(*the slope from the other equation*)x+b. For both equations plug in a corresponding x and y coordinate given on the list (y1 and y2 would be consecutive coordinates, so 1 and 2, and same for x1 and x1, so -9 and -13). You should get (-4/1) for the slope, and when you plug that into the other equation you should get 5. Lastly you plug all these numbers into y=mx+b, and you get your answer.

Hope this helps :)

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2 years ago

Giá trị x thoả mãn x(x − 3) + x − 3 =0 là

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Here we will use the trial and error method.

We will try putting different values of x.

$\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}$

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$\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}$

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$\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}$

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<h2>Again,</h2><h3>x=3</h3>

$\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}$

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2 years ago

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A) The perimeter is the length around the rectangle, so it would be 2 + 5 + 2 + 5 = 14m

The area is 2m * 5m = 10m^2

b/c) You have to draw a rectangle with a perimeter of 14m, and an area that ISN'T 10m^2. You could draw a 3m by 4m rectangle which would have a perimeter of 14m and an area of 12m^2.

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3 years ago

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user100 [1]

So I'll walk through the first 2. Then please try the other ones and let me know if you run into more problems.

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If m is equal to 7, then replace m with 7.

5(7)-6

5x7=35 so the expression is now 35-6. Solve.

35-6=29

So that was the first one.

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We just do what we do with the first problem.

4(7)+(2)

4x7=28 so the expression is 28+2.

28+2=28

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hope it helps

p.s. When there is subtraction, add. When there is division, multiply to cancel that out. When there is multiplication, divide to cancel. etc.

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