The point that the graphs of f and g have in common are (1,0)
<h3>How to get the points?</h3>
The given functions are:
f(x) = log₂x
and
g(x) = log₁₀x
We know that logarithm of 1 is always zero.
This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1
Therefore the point the graphs of f and g have in common is (1,0).
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First, find m, the slope of the line.
(1-3)/(5-1) =
-2/4 =
-1/2
Next, choose either point to write the point slope form. I will show the outcome of both points.
1. Using point (1, 3)
y-y1=m(x-x1)
y-3=(-1/2)(x-1)
————————
y-3=-1/2x+1/2
y=-1/2x+7/2
2. Using point (5,1)
y-y1=m(x-x1)
y-1=-1/2(x-5)
————————
y-1=-1/2x+5/2
y=-1/2x+7/2
The outcome is the same.
They give the formula as:
Surface Area =<span> (2 • <span>π <span>• r²) + (2 • <span>π • r • height)</span></span></span></span>
However the 2*PI*r^2 part of the formula is used to calculate the 2 "ends" of a cylinder. Since the problem states that you are NOT to count any of surface area of the "ends" then you only need the <span>(2 • <span>π • r • height) part of the formula.
So, r = 3 inches and height = 8 * 3 inches, the side area equals
2 * PI * r * height
2 * 3.14159 * 3 * 24 =
</span></span>
<span>
<span>
<span>
452.39 cubic inches which is the lateral area.</span></span></span>
Answer:
D. 16 ft
Step-by-step explanation:
h = √20² - (24/2)² = √400-144 = √256 = 16
