The area of a square is: A = s^2
With side being s = 20m
A = 20^2m^2 = 400m^2
Hope that helps! :)
3x + 8 = 9 + 4x :First, subtract the 8 over to the right
3x = 1 + 4x :Then, subtract the 4x over to the left
-x = 1 :Then, divide the whole equation by the -1 attached to the x
<em><u>x = -1</u></em>
<span>Minimum wykresu funkcji kwadratowej znajduje się w ( -1, 2). Punkt ( 2 , 20) jest również od paraboli. Która funkcja reprezentuje sytuację?
</span><span>Canonical form of the function
</span>f(x) = a* (x - p)² + q
A .f(x) = (x + 1)² + 2 ⇔ p= -1 , q = 2
B. f(x) = (x – 1)² + 2 we reject
C. f(x) = 2(x + 1)² + 2 ⇔ p = -1 , q = 2
D .f(x) = 2(x – 1)² + 2 we reject
The point (2,20) substitute
A f(x) = (x +1)² + 2
20 = (2 + 1 )² + 2
20 ≠ 9 +2
20 ≠ 11 we reject
D f(x) = 2* (x + 1)² + 2
20 = 2* (2+1)² + 2
20 = 2 * 3² + 2
20 = 2 * 9 + 2
20 = 18 + 2
Reply C
Median:
The median in this set is the 5th term.
Therefore the median in this set is 23.
