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Oduvanchick [21]

3 years ago

11

The cost of renting a bike at the plaza is $4 plus $1.50 per hour. Write an equation in slope- intercept form that models the co

st of renting a bike. In a table format, find the range of the situation for the following domain . In the table include your independent and dependent variables.

1 answer:

horsena [70]3 years ago

6 0

Answer:

u can also get it on google like i did, dont cheat, etc. its not good

Step-by-step explanation:

Total Cost = (hourly rate)*(number of hours) + Fixed Initial Cost

y = 1.50x + 4

So the equation is y = 1.50x + 4

Plug in x = 12 to find y

y = 1.50x + 4

y = 1.50*12 + 4

y = 18 + 4

y = 22

It will cost $22 total to rent the bike for 12 hours.

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Answer for the points<br> 6 − (9 − 2) + 3 × 6

AfilCa [17]

Answer:

17

Step-by-step explanation:

USING BIDMAS (Brackets Indices Division Multiplication Addition Subtraction)

6 − (9 − 2) + 3 × 6

9-2=7

3x6=18

6-7+18=17

8 0

3 years ago

K(x) = 6x+100 k(-5) =

kkurt [141]

Answer:

$k(-5)=70$

Step-by-step explanation:

The given function is

$k(x)=6x+100$

To find k(-5), we put x=-5 into the given function to get;

$k(-5)=6(-5)+100$

Multiply out to obtain;

$k(-5)=-30+100$

This is the same as;

$k(-5)=100-30$

This simplifies to

$k(-5)=70$

3 0

3 years ago

A research team is testing whether a fuel aditive increases a car's gas mileage. The maker of the additive claims that the addit

Thepotemich [5.8K]

Answer:

Yes there is sufficient evidence to reject the company's evidence

Step-by-step explanation:

From the question we are told that

The sample size is n = 25

The mean is $\= x = 5.3 \ mpg$

The standard deviation is $\sigma = 1.8 \ mpg$

The z-score is z = -1.94

The null hypothesis is $H_o : \mu = 6 \ mpg$

The alternative hypothesis is $H_a : \mu \ne 6$

Generally the p-value is mathematically evaluated as

$p-value = 2 * P( Z$

From the z table the area under the normal curve to the left corresponding to -1.94 is

$P( Z$

=> $p-value = 2 * 0.02619$

=> $p-value = 0.052$

Let assume the level of significance is $\alpha = 0.05$

Hence the $p-value > \alpha$ this mean that

The decision rule is

Fail to reject the null hypothesis

The conclusion is

There is sufficient evidence to reject the company's evidence

5 0

3 years ago

Julie made identical necklaces out of shell she collected at the beach all together she we use 10 Brown shells 15 black shells a

Lelu [443]

Answer:

Therefore the number of brown shells in each necklace was = 2 brown shells.

Step-by-step explanation:

If Julie made identical necklaces then we can say that number of each different colored shells were equally distributed among the necklaces.

So we can say that to find the number of necklaces we have to find the GCD (greatest common denominator) of the different colored shells.

Therefore the GCD of 10, 15 and 20 is 5.

Therefore Julia made 5 necklaces.

Therefore the number of brown shells in each necklace was = $\frac{10}{5}$ = 2 shells.

4 0

4 years ago

As a follow-up to a report on gas consumption, a consumer group conducted a study of SUV owners to estimate the mean mileage f

kondor19780726 [428]

Answer:

The 95% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

Step-by-step explanation:

Our sample size is 96.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 96-1 = 95$

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 95 and 0.025 in the t-distribution table, we have $T = 1.9855$ .

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{5.6}{\sqrt{96}} = 0.57$

Now, we multiply T and s

$M = T*s = 1.9855*0.57 = 1.31$

For the lower end of the interval, we subtract the mean by M. So $19.6 - 1.31 = 18.29$

For the upper end of the interval, we add the mean to M. So $19.6 + 1.31 = 20.91$

The 95% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

8 0

4 years ago