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Oxana [17]
3 years ago
6

A vegetable farmer fills of a wooden crate with of a pound of tomatoes. How many pounds of tomatoes can fit into one crate?

Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0

Answer:

a and d

Step-by-step explanation:

The crate can carry any amount up to a pound. Since both b and c are over 1, they can immediately be eliminated. Since both a and d are lower than 1 they can be the answers. if the question tells you to pick all possible answers, pick both a and d but if it says pick one answer, pick a since it is the closest to one pound.

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D, it’s a function because the Y and X values have its own numbers , and vertical are functions . Horizontal is not a function
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3 years ago
In the adjoining figure, ABCD is a square of side 28 cm find the area of shaded region​
vodka [1.7K]

Step-by-step explanation:

Area of square

A = s²

A = 28²

A = 28 × 28

A = 784 cm²

7 0
2 years ago
If n = 6, then the value of n 2 is 12.<br> true or false
Vesna [10]
The answer is false. n^2 would become 6^2 which is equal to 36 not 12

8 0
3 years ago
How many hours of training would you need to have a monthly pay of $1500. (Hours of Training 10. Monthly pay 1220.)
White raven [17]

Answer:you will need about 12.29508197 hours of training

Step-by-step explanation:

7 0
3 years ago
Agan Interior Design provides home and office decorating assistance to its customers. In normal operation, an average of 2.3 cus
likoan [24]

Given Information:

Average customer arrival = λ =2.3 customers/hour

Average consultant time1 = μ  = 8 minutes/customer

Average consultant time2 = μ  = 10 minutes/customer

Cost of consultants service = $16

Cost of customer waiting time = $25

Required  Information:

Use one consultant with an average service time of 8 minutes/customer or use two consultants, each with average service time of 10 minutes/customer ?

Answer:

it is recommended to use one consultant with an average service time of 8 minutes/customer.

Step-by-step explanation:

Convert the average consultant time to hours/customer

Average consultant time1 = μ  = 60/8 = 7.5 hours/customer

Average consultant time2 = μ  = 60/10 = 6 hours/customer

Single consultant queuing model:

Calculations for one consultant

Average no. of customers waiting for service = Lq = λ²/μ(μ-λ)

Average no. of customers waiting for service = Lq = (2.3)²/7.5(7.5 - 2.5)

Average no. of customers waiting for service = Lq = 0.1356

Average no. of customers in the system = L = Lq + λ/μ

Average no. of customers in the system = L = 0.1356 + 2.3/7.5

Average no. of customers in the system = L = 0.442

Total cost = (customer waiting time cost)*L + consultant service cost

Total cost = $25*0.442 + $16

Total cost = $27.05

Multi consultant queuing model:

Calculations for two consultants

Average no. of customers waiting for service = Lq = ((λ/μ)^k(λμ)/(k -1)(kμ - λ))*P₀

Where k = 2 is the number of consultants and P₀ is the probability that all of the k consultants are idle. The value of P₀  can be found in the tables with λ/μ = 2.3/6 = 0.38 and k = 2,  P₀ ≅ 0.685

Average no. of customers waiting for service = Lq = (2.3/6)²(2.3*6)/(2-1)(2*6 - 2.3)*0.685

Average no. of customers waiting for service = Lq = 0.1431

Average no. of customers in the system = L = Lq + λ/μ

Average no. of customers in the system = L = 0.1431 + 2.3/6

Average no. of customers in the system = L = 0.5264

Total cost = (customer waiting time cost)*L + consultant service cost

Total cost = $25*0.5264 + ($16)*2 (since there are 2 consultants now)

Total cost = $45.16

Conclusion:

Therefore, it is recommended to use one consultant with an average service time of 8 minutes per customer since the total cost is less than the other option.

3 0
3 years ago
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