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murzikaleks [220]
3 years ago
5

Please help!!! 100 points if correct!!! please actually answer

Mathematics
1 answer:
rosijanka [135]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

What is the theoretical probability that the family has two dogs or two cats? (1/2)

The choices are dd, dc, cd, cc

There are 4 choices = dd or cc/ total = 2/4 = 1/2

Let the heads of the coin be dogs and the tails of a coin be cats

Flip two coins and coin A is the first pet and coin B is the second pet

heads , heads = 10

heads, tails  14

tails heads  =13

tails tails =  13

          total 50

Experimental probability  2 dogs or 2 cats = ( hh, tt) /total = ( 10+13) /50 =                    23/50

If we had 3 pets  

what is the theoretical probability that they have three dogs or three cats?

ddd, ddc, dcd, dcc, ccc, ccd ,cdc, cdd

There are 8 options

 ddd or ccc/ total = 2/8 = 1/4

Let the heads of the coin be dogs and the tails of a coin be cats

Flip three coins and coin A is the first pet and coin B is the second pet Coin C be the third pet

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