What is the mean absolute deviation?
The mean absolute deviation is 2.2!
Hope this helps!
Answer:
f) Not possible
Step-by-step explanation:
The triangles can be shown to be similar by SAS, but the corresponding sides are not marked as congruent. With the given information, it is not possible to show the triangles are congruent.
Step-by-step explanation:
(a) dP/dt = kP (1 − P/L)
L is the carrying capacity (20 billion = 20,000 million).
Since P₀ is small compared to L, we can approximate the initial rate as:
(dP/dt)₀ ≈ kP₀
Using the maximum birth rate and death rate, the initial growth rate is 40 mil/year − 20 mil/year = 20 mil/year.
20 = k (6,100)
k = 1/305
dP/dt = 1/305 P (1 − (P/20,000))
(b) P(t) = 20,000 / (1 + Ce^(-t/305))
6,100 = 20,000 / (1 + C)
C = 2.279
P(t) = 20,000 / (1 + 2.279e^(-t/305))
P(10) = 20,000 / (1 + 2.279e^(-10/305))
P(10) = 6240 million
P(10) = 6.24 billion
This is less than the actual population of 6.9 billion.
(c) P(100) = 20,000 / (1 + 2.279e^(-100/305))
P(100) = 7570 million = 7.57 billion
P(600) = 20,000 / (1 + 2.279e^(-600/305))
P(600) = 15170 million = 15.17 billion
Answer:
There are 30 temporary employees
Step-by-step explanation:
<em>To find </em><em>x% of quantity A</em><em>, multiply x% by A after change x% to the normal number by divide it by 100 ⇒ </em><em>(x ÷ 100) × A</em>
Let us use this rule to solve the question
∵ The local water slides have 100 employees
∵ 30% of them are temporary
∴ The number of temporary employees = 30% × 100
∵ 30% = 30 ÷ 100 = 0.30
∴ The number of temporary employees = 0.30 × 100
∴ The number of temporary employees = 30
∴ There are 30 temporary employees
