Answer:
$200
Step-by-step explanation:
You can take .1 times $2000 since 1-tenth is equal to .1
or you can 1 over ten times 2000 over 1 which makes 2000 over 10 and you divide 2000 by 10 to get $200
113 groups, since the place value of the 4 is divisible by 4 you can predict that the quotient is about 100
<span>1. D. Concave Hexagon
2.
(n - 2)180 = 2160
n - 2 = 12
n = 14
</span>
<span>C. 14
3.
</span><span><span>(n - 2)180 = 3060
n - 2 = 17
n = 19
</span>
<span>D. 19
4.
[(n - 2)180]/n =
</span></span><span>= [(15 - 2)180]/15
= 13(180)/15
= 156
</span>
<span>C. 156°</span>
Answer:
a) dx/dt = kx*(M - h/k - x)
Step-by-step explanation:
Given:
- The harvest differential Equation is:
dx/dt = kx*(M-x)
Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In other words we harvest hx per unit of time for some h > 0
Find:
a) Construct the differential equation.
b) Show that if kM > h, then the equation is still logistic.
c) What happens when kM < h?
Solution:
- The logistic equation with harvesting that is proportional to population is:
dx/dt = kx*(M-x) hx
It can be simplified to:
dx/dt = kx*(M - h/k - x)
- If kM > h, then we can introduce M_n=M -h/k >0, so that:
dx/dt = kx*(M_n - x)
Hence, This equation is logistic because M_n >0
- If kM < h, then M_n <0. There are two critical points x= 0 and x = M_n < 0. Since, kx*(M_n - x) < 0 for all x<0 then the population will tend to zero for all initial conditions
Answer:
12 hours
Step-by-step explanation:
1 : (1/4 : (2 + 1)) = 12
