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Juli2301 [7.4K]
3 years ago
5

Three balls are selected at random without replacement from an urn containing two white balls and four blue balls. Find the prob

ability of the given event. All of the balls are blue.
Mathematics
1 answer:
guapka [62]3 years ago
4 0

<u>Answer:</u>

P(3 blue) = 1/5

<u>Steps:</u>

P(3 blue) = 2/3 × 3/5 × 1/2

P(3 blue) = 6/30

P(3 blue) = 1/5

<em>that's 20%</em>

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Answer:

M = (Y2 - Y1) / (X2 - X1)

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3 years ago
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3 years ago
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insens350 [35]

Answer:

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5 0
3 years ago
-8(8v + 1) - 2 = -394
Bess [88]

Answer:

v = 6

Step-by-step explanation:

Solve for v:

-8 (8 v + 1) - 2 = -394

-8 (8 v + 1) = -64 v - 8:

-64 v - 8 - 2 = -394

Grouping like terms, -64 v - 8 - 2 = -64 v + (-8 - 2):

-64 v + (-8 - 2) = -394

-8 - 2 = -10:

-10 - 64 v = -394

Add 10 to both sides:

(10 - 10) - 64 v = 10 - 394

10 - 10 = 0:

-64 v = 10 - 394

10 - 394 = -384:

-64 v = -384

Divide both sides of -64 v = -384 by -64:

(-64 v)/(-64) = (-384)/(-64)

(-64)/(-64) = 1:

v = (-384)/(-64)

The gcd of -384 and -64 is -64, so (-384)/(-64) = (-64×6)/(-64×1) = (-64)/(-64)×6 = 6:

Answer:  v = 6

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4 years ago
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