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olganol [36]
3 years ago
5

Matrix question please help

Mathematics
1 answer:
lyudmila [28]3 years ago
7 0

Answer:

I don't know this answer please help hand

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What is the sum?<br> 8+(-12)<br> -20<br> 24<br> 4<br> 20
blagie [28]

Answer:

-4

Step-by-step explanation:

adding a negative is the same as subtracting a positive

<h2><u><em>xoxo, </em></u></h2><h2><u><em>your highness...</em></u></h2>
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The slope of a line is. What is the slope of a line that is parallel to it?
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Are the lines horizontal, diagonal or vertical
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Sacramento County high school seniors have an average SAT score of 1,020. From a random sample of 144 Sacramento High School stu
kari74 [83]

Answer:

We need to conduct a hypothesis in order to check if the high school students are representative of the overall population (or if the true mean is 1020 or not), the system of hypothesis would be:    

Null hypothesis:\mu = 1020    

Alternative hypothesis:\mu \neq 1020  

Step-by-step explanation:

Previous concepts  and data given  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=1100 represent the sample mean    

s=144 represent the sample standard deviation  

n=144 represent the sample selected  

\alpha significance level    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the high school students are representative of the overall population (or if the true mean is 1020 or not), the system of hypothesis would be:    

Null hypothesis:\mu = 1020    

Alternative hypothesis:\mu \neq 1020    

If we analyze the size for the sample is > 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic  

We can replace in formula (1) the info given like this:    

t=\frac{1100-1020}{\frac{144}{\sqrt{144}}}=6.67      

P-value  

First we need to calculate the degrees of freedom given by:

df=n-1=144-1 =143

Then since is a two sided test the p value would be:    

p_v =2*P(t_{144}>6.67)=2.59x10^{-10}    

Conclusion    

If we compare the p value and a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is significant different from 1020 at 5% of significance.    

6 0
3 years ago
From her purchased bags, Rory counted 110 red candies out of 550 total candies. Using a 90% confidence interval for the populati
Svetlanka [38]

Answer:

The Confidence Interval = (0.172, 0.228)

Where:

The lower limit = 0.172

The upper limit = 0.228

Step-by-step explanation:

The formula to be applied or used to solve this question is :

Confidence Interval formula for proportion.

The formula is given as :

p ± z × √[p(1 - p)/n]

n = Total number of red candies = 550 red candles

p = proportion = Number of red candies counted/ Total number of red candies

= 110/550 = 1/5 = 0.2

z = z score for the given confidence interval.

We are given a confidence interval of 90%. Therefore, the z score = 1.6449

Confidence Interval = p ± z × √[p(1 - p)/n]

Confidence Interval = 0.2 ± 1.6449 × √[0.2(1 - 0.2)/550]

= 0.2 ± 1.6449 √0.2 × 0.8/550

= 0.2 ± 1.6449 × 0.0170560573

= 0.2 ± 0.0280555087

Hence, the Confidence Interval = 0.2 ± 0.0280555087

0.2 - 0.0280555087 = 0.1719444913

Approximately = 0.172

0.2 + 0.0280555087 = 0.2280555087

Approximately = 0.228

Therefore, the Confidence Interval = (0.172, 0.228)

Where:

The lower limit = 0.172

The upper limit = 0.228

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3 years ago
ANSWER ASAP Choice 1 Choice 2 Choice 3 Choice 4
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Answer : Use an app like PhotoMath
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