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Delicious77 [7]

4 years ago

10

the princaipal at oak school ordered 25 pizzas for the fourth grade claasses share he will deliver an equal number of pizzas to

each of 8 classes how many pizzas willeach class receive divide to find the quotient and remainder decide how to use the quotient and remainder to answer the question

1 answer:

Norma-Jean [14]4 years ago

7 0

Each class would get 3 1/8 pizza

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Help me with this pls

Pachacha [2.7K]

Step-by-step explanation:

b can be used to check her score

6 0

3 years ago

Please show all steps and explain what you did thoroughly, thank you for your time and help.

Makovka662 [10]

Answer:

Step-by-step explanation:

1) x² + 6x + 11 = 0

a = coefficient of x² = 1

b = coefficient of x = 6

c = Constant = 11

Roots = (-b ± √b² - 4ac)/2a

$D = \sqrt{b^{2}-4ac}\\\\=\sqrt{6^{2}-4*1*11}\\\\=\sqrt{36-44}\\\\=\sqrt{-8}\\\\=\sqrt{8i^{2}}\\\\ = 2i\sqrt{2}$

Roots = $\dfrac{-6 \± 2i\sqrt{2}}{2}\\$

$= \dfrac{2(-3 \± i\sqrt{2})}{2}\\\\=-3 \± i\sqrt{2}$

2) 2x² - 16x = 50

Divide the whole equation by 2

x² - 8x = 25

Divide the coefficient of x (i. e 8 ) by 2 = 8/2 = 4, Now add 4 to both sides of the equation

x² - 8x + 4 = 25 + 4

x² - 2*4*x + 2² = 29

(x - 2)² = 29

Take square root both side

$x - 2 = \± \sqrt{29}\\\\x = 2 \± \sqrt{29}$

8 0

3 years ago

In 3/4 cup of oatmeal, that is 1/10 of the recommended daily value of iron. What faction of the daily recommended value of iron

Nastasia [14]

Answer:

recommended value of iron is $\frac{2}{15}$

Step-by-step explanation:

In 3/4 cup of oatmeal, that is 1/10 of the recommended daily value of iron

The ratio of cup of oatmeal to the value of iron is

$\frac{\frac{3}{4}}{\frac{1}{10} } =\frac{30}{4}$

Let x be the recommended value of iron for 1 cup of oatmeal

Make a proportion

$\frac{oatmeal}{value} =\frac{oatmeal}{value}$

$\frac{30}{4} =\frac{1}{x}$

cross multiply

$30x=4$

$x=\frac{4}{30}$

$x=\frac{2}{15}$

recommended value of iron is 2/15

3 0

4 years ago

The nth term of a sequence is 2n-1.

Zinaida [17]

Answer:

25,31,37

Step-by-step explanation:

n should be positive integer number. The three numbers in both sequences have different term number n but same value. We can equalize each nth term in the question to "a" which represents one of the three numbers.

a=2n-1, then n=(a+1)/2

a=3n+1, then n=(a-1)/3

remember the two n above are different but both should be positive integer. That means, we have to find the "a" number that gives me an integer n for the first equation. The possible numbers between 20 to 40 are 22,25,28,31,34,37,40.

The possible numbers for the second equation are 21,23,25,27,29,31,33,35,37,39.

Now find the common numbers between the two sets above. They are 25,31,37

6 0

3 years ago

Suppose that you want to estimate the mean pH of rainfalls in an area that suffers from heavy pollution due to the discharge of

labwork [276]

Answer:

The number of rainfalls is $n =96$

The answer to the second question is no it will not be valid this because from the question we are told that the experiment require one pH reading per rainfall so getting multiply specimens(used for the pH reading) from one rainfall will make the experiment invalid.

Step-by-step explanation:

from the question we are told that

The standard deviation is $\sigma = 0.5$

The margin of error is $E = 0.1$

Given that the confidence level is 95% then we can evaluate the level of significance as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha =0.05$

Next we will obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table , the value is $Z_{\frac{\alpha }{2} } = 1.96$

Generally the sample size is mathematically represented as

$n = [\frac{Z_{\frac{\alpha }{2} * \sigma }}{ E} ]^2$

substituting values

$n = [\frac{1.96 * 0.5 }{ 0.1} ]^2$

$n =96$

The answer to the second question is no the validity is null this because from the question we are told that the experiment require one pH reading per rainfall so getting multiply specimens(used for the pH reading) from one rainfall will make the experiment invalid

5 0

4 years ago