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pantera1 [17]
3 years ago
13

if a cart started rolling down a hill at 2 m/s, and 5 seconds later it was moving at 12 m/s, what was the carts accelaration

Mathematics
1 answer:
irga5000 [103]3 years ago
7 0

Answer:

2 m/s^2

Step-by-step explanation:

Acceleration is the rate at which the speed changes.

a = (new speed - old speed)(time)

a = (12 m/s - 2 m/s)/(5 s)

a = (10 m/s)/(5 s)

a = 2 m/s^2

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Nadya [2.5K]

   First of all in order for us to figure out what angle x is we need to find the formula for finding that specific type of angle.

Formula is...

x = (far arc - close arc) ÷ 2

Now we just need to plug in.

x = (172° - 52°) ÷ 2 =

x = 120° ÷ 2 = 60°

Your answer: x = 60°

Good Luck! :)

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6 0
3 years ago
Price for restaurant bill
Alik [6]

Answer:

for what food??

Step-by-step explanation:

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3 years ago
I NEED HELP EXPLAINING HOW I GOT MY ANSWER ILL GIVE 100 POINTS PLEASEEE?!?!?
attashe74 [19]

Answer:

<h2>h =  \frac{S - 2πr²}{2\pi r}</h2>

Step-by-step explanation:

S = 2πr² + 2πrh

<u>Move 2πr² to the left side of the equation</u>

That's

2πrh = S - 2πr²

<u>Divide both sides by 2πr to make h stand alone</u>

That's

<h3>\frac{2\pi rh}{2\pi r}  =  \frac{S - 2πr²}{2\pi r}</h3>

We have the final answer as

<h3>h =  \frac{S - 2πr²}{2\pi r}</h3>

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6 0
4 years ago
Use a graphing calculator to solve the equation -2sin(theta)= 1.2 in the interval from 0 to 2pi.
elena-s [515]

Answer:

\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64  

Step-by-step explanation:

As you can see from the graph I attached you, the possible solutions in the interval from 0 to 2π are approximately:

\theta=3.7\\\\and\\\\\theta=5.7

So, it's useful to solve the equation too, in order to verify the result:

-2sin(\theta)=1.2\\\\sin(\theta)=-\frac{3}{5}

Taking the inverse sine of both sides:

\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64

Using this result we can conclude the solutions in the interval from 0 to 2π are approximately:

\theta\approx 3.785\\\\\theta \approx 5.64

8 0
3 years ago
Find the kilograms in 4000g​
ziro4ka [17]

Answer:

4,000,000

Step-by-step explanation:

There are 1,000 grams in a kilogram

So, multiply 4,000 x 1,000

And you get 4,000,000

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3 years ago
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