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3 years ago

What is the value of x in the product of powers below? 6^9 6^x=6^2 -11 -7 11 7

Mathematics

2 answers:

Elodia [21]3 years ago

8 0

Answer:

x = - 7

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$

Given

$6^{9}$ × $6^{x}$ = 6², then

$6^{(9+x)}$ = 6²

Since the bases on both sides are equal then equate the exponents

9 + x = 2 ( subtract 9 from both sides )

x = - 7

soldi70 [24.7K]3 years ago

4 0

Answer: -7

Step-by-step explanation:

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What ratio is equivalent to TanA?

USPshnik [31]

Answer:

24/10

Step-by-step explanation:

From the diagram

Opposite BC = 24cm

Adjacent = AC = 10cm

tan theta = opposite/adjacent

Substitute

tan <A = BC/AC

tan <A = 24/10

Hence the equivalent ratio is 24/10

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3 years ago

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Answer:

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3 years ago

A triangle has angles measuring 23 and 48 degrees. What is the measure of the third angle?

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Answer:

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Step-by-step explanation:

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2 years ago

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plain why the function is discontinuous at the given number a. (Select all that apply.) f(x) = x2 − 2x x2 − 4 if x ≠ 2 1 if x =

ElenaW [278]

Answer with Step-by-step explanation:

We are given that

$f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.$

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

$f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}$

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}$

$\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}$

Right hand limit =RHL when x> 2

Substitute

x=2+h

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}$

$=\frac{2}{4}=\frac{1}{2}$

LHL=RHL= $\frac{1}{2}$

f(2)=1

$LHL=RHL\neq f(2)$

Hence, function is discontinuous at x=2

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3 years ago

Below are three different hypothesis tests about population proportions. For each test, use StatKey and the information given to

Ilia_Sergeevich [38]

Answer:

1a) p-hat=0.38

1b) P=0.08

1c) The null hypothesis is not rejected

2a) p-hat=0.64

2b) P=0.0027

2c) The null hypothesis is rejected

3a) p-hat=0.55

3b) P=0.153

3c) The null hypothesis is not rejected

Step-by-step explanation:

(1) H0: p = 0.3 vs Ha: p ≠ 0.3. In their survey, they had a count of 38 using a sample size n=100.

1a) The p-hat is p-hat=38/100=0.38.

1b) The standard deviation is

$\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.3*0.7}{100}}=0.046$

The sample size is n=100.

The z-value is:

$z=\frac{\hat{p}-p}{\sigma}=\frac{0.38-0.3}{0.046}=\frac{0.08}{0.046}= 1.74$

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.74 is P=0.08.

1c) The null hypothesis is not rejected.

(2) H0: p = 0.7 vs Ha: p ≠ 0.7. In their survey, they had a count of 320 using a sample size n=500.

2a) The p-hat is p-hat=320/500=0.64.

2b) The standard deviation is

$\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.7*0.3}{500}}=0.02$

The sample size is n=500.

The z-value is:

$z=\frac{\hat{p}-p}{\sigma}=\frac{0.64-0.7}{0.02}=\frac{-0.06}{0.02}=-3$

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=3 is P=0.0027.

2c) The null hypothesis is rejected.

(3) H0: p = 0.6 vs Ha: p < 0.6. In their survey, they had a count of 110 using a sample size n=200.

2a) The p-hat is p-hat=110/200=0.55.

2b) The standard deviation is

$\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.6*0.4}{200}}=0.035$

The sample size is n=200.

The z-value is:

$z=\frac{\hat{p}-p}{\sigma}=\frac{0.55-0.6}{0.035}=\frac{-0.05}{0.035}=-1.43$

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.43 is P=0.153.

2c) The null hypothesis is not rejected.

8 0

3 years ago