In order for the product of some numbers to end in a zero, the prime factors of ... So 1 x 2 x 3 x ... x 98 x 99 x 100 (AKA 100!) has 24 zeroes at the end
Givens
Let the smallest integer = x
The middle integer = x + 1
The largest integer = x + 2
Remark
The first phrase up to is says the sum of ... The key word is sum. So far you have x + x + 1 + x + 2. Simplified this comes to 3x + 3.
Two times the 2nd number is 2*(x + 1) and from that, subtract 14
2(x + 1) - 14
If you break down each phrase as I have done you will soon become very good at doing these types of problems.
So the equation looks like this.
Solution
3x + 3 = 2(x + 1) - 14 Remove the brackets.
3x + 3 = 2x + 2 - 14 Combine the like terms on the right.
3x + 3 = 2x - 12 Subtract 3 from both sides.
3x = 2x - 12 - 3
3x = 2x - 15 Subtract 2x from both sides.
3x - 2x = - 15
x = -15 <<<< Answer for smallest number.
Answer
-15
- 14
-13 Are the three numbers you seek.
Answer:
Step-by-step explanation:
