We need to determine the radius and diameter of the circle. If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,
A = 10 pi in^2 = pi*r^2. Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.
Thus, the diam. of the circle is 2sqrt(10) in. This diam. has the same length as does the hypotenuse of one of the triangles making up the square.
Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square. So, 4(10) in^2 = 2x^2. Then:
40 in^2 = 2x^2, or 20 in^2 = x^2, and so the length x of one side of the square is sqrt(20). The area of the square is the square of this result:
Area of the square = x^2 = [ sqrt(20) ]^2 = 20 in^2 (answer). Compare that to the 10 pi sq in area of the circle (31.42 in^2).
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Yes it is congruent to5x-1
Answer:
The inequality that represents the age of the group, "x", is: 
Step-by-step explanation:
To express this problem in an inequality we will attribute the age of the members on the group with the variable "x". There are two available information about "x", the first states that every member of the group is older than 17 years, therefore we can create a inequality based on that:

While the second data from the problem states that none of than is older than 54 years old, this implies that they can be at most that old, therefore the inequality that represents this is:

In order for both to be valid at the same time x must be greater than 17 and less or equal to 54, therefore we finally have:

Answer:
It's different because the experiment is more accurate as it progresses.
Step-by-step explanation:
You'll notice that the higher the numbers get in the experiment the closer it gets to your solution. The theoretical probability of flipping a coin is about 50% heads and 50% tails, but it doesn't always seem like that in an experiment. The experimental probability from your experimentation so far would be 62% of heads and 38% of tails.