Is there more to the problem? There isn’t enough information here.
If the square has sides of 6 the circle has a radius of 3 so it's area is 9pi
I think a would be 115 degrees. B would be 71 degrees. I think the second question would be c.
X^2 -6x -8 is a parabola in ax^2 + bx + c form
The axis of symmetry is -b/2a = 3
The vertex is (3,f(3)) = (3,-17)
The x-intercept is f(x)= 0 where x=-1.123, 7.123
Graphing: it opens upwards
Answer:
![\sqrt[4]{2}^{3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D%5E%7B3%7D)
Step-by-step explanation: