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Over [174]
3 years ago
14

An exit poll of 1000 randomly selected voters found that 515 favored measure A. a. Construct a 99% confidence interval for the s

upport of measure A. b. Suppose measure A needs at least 50% support to pass, what are the null and alternative hypotheses if we were to test to see if measure A will pass? c. Compute the p-value of the above test.
Mathematics
1 answer:
never [62]3 years ago
6 0

Answer:

Step-by-step explanation:

Given that an  exit poll of 1000 randomly selected voters found that 515 favored measure A.

Sample proportion p = \frac{515}{1000} =0.515

q=1-0.515 =0.485\\n =1000\\SE = \sqrt{\frac{pq}{n} } \\=0.158\\

Margin of error 99% = 2.58*SE

=2.58*0.0158\\=0.0408

99% confidence interval =(0.515-0.0408, 0.515+0.0408)\\= (0.474, 0.556)

------------------------

H_0: p =0.5\\H_a: p >0.5\\

(Right tailed test)

STd error = \sqrt{\frac{0.5*0.5}{1000} } \\=0.0158

Test statistic Z = p diff/std error =\frac{0.015}{0.0158} \\\\=0.9487

p value = 0.1714

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