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4 years ago

What type of triangle is shown below?

Mathematics

2 answers:

Scorpion4ik [409]4 years ago

4 0

That's a right angled triangle.
Hope this helps!

Ahat [919]4 years ago

3 0

Right triangle cause it has a right angle

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Help! Please ASAP !!!!!

VladimirAG [237]

You must do work presented inside parentheses first. Thus, do this first: (-5-7).

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4 years ago

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Jacob and Ali want to run from one corner of a football field to the opposite corner. The rectangular football field is 50 yards

svet-max [94.6K]

Answer:

Jacob ran 40 yards more than Ali.

Step-by-step explanation:

Football field is in the shape of a rectangle having dimensions 120 yards × 50 yards

Since Jacob runs around the perimeter of the field from one corner to other corner, therefore, distance run by Jacob = $(\text{Length+width})$

Distance run by Jacob = 50 + 120 = 170 yards

Ali runs through the middle of the field diagonally on a straight line.

Therefore, distance covered by Ali = $\sqrt{\text{length}^{2}+\text{width}^{2}}$

= $\sqrt{(50)^{2}+(120)^{2}}$

= $\sqrt{2500+14400}$

= $\sqrt{16900}$

= 130 yards

Now difference between the distance covered by Jacob and Ali

= 170 - 130

= 40 yards

Therefore, Jacob ran 40 yards more than Ali.

7 0

3 years ago

I have 5 minutes to put the answer in

Sholpan [36]

Answer:

-8

Step-by-step explanation:

Y=mx+b, m=slope

in this case -8 is the m

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3 years ago

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A cash box contains $74 made up of quarters, half-dollars, and one-dollar

Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

$0.25q+0.50h+1.00d=74$

$\displaystyle{h=\frac{3}{5}d+1}$

$q=4(d+h)$

Then, substitute q in the first equation with the expression from the third equation:

$0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74$

Next, substitute h in that equation with the expression from the second equation:

$\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}$

$2d+0.9d+1.5=74\\2.9d+1.5=74$

Solve for d, the number of one-dollar coins:

$2.9d+1.5=74\\2.9d=72.5\\d=25$

Substitute 25 for d in the second equation to find h, the number of half-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{h=\frac{3}{5}(25)+1}$

$h=15+1\\h=16$

Substitute 25 for d and 16 for h in the third equation to find q, the number of quarters:

$q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164$

Then, verify that the coins total $74:

$0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}$

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{16=\frac{3}{5}(25)+1}$

$16 = 15 + 1\\16 = 16\\\text{Check.}$

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

$q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}$

6 0

3 years ago

AHH HELP ME AGAIN :P THERES ONE MORE AFTER THIS

mihalych1998 [28]

Answer:

26.25

Step-by-step explanation:

y = 8.75(3)

y = 26.25

6 0

3 years ago

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