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Kitty [74]
3 years ago
14

Plz help me plzzzz I need it

Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0

Step-by-step explanation:

y= 30x + 180

there is no solution to represent Karen which is 4x + 100

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one rectangle measures 2 units by 7 units. a second rectangle measures 11 units by 37 units. are these two figures scaled versio
Amanda [17]

Answer: The both triangle are not scale version to each other.

Explanation:

It is given that the one rectangle measures 2 units by 7 units. a second rectangle measures 11 units by 37 units.

The two shapes are scaled version of each other if their corresponding sides are in same proportion. In other words the if two shapes scaled version of each then the shapes are similar.

The sides or first rectangle are 2 and 7. The measures of second rectangle are 11 and 37.

The proportion of small side is,

\frac{2}{11}

The proportion of large side is,

\frac{7}{37}

So,

\frac{2}{11}\neq \frac{7}{37}

Since the proportion are not equal, therefore  both triangle are not scale version to each other.

6 0
3 years ago
Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students
Nezavi [6.7K]

Answer: A. 85.7

Step-by-step explanation:

Given : Two sections of a class took the same quiz.

Section A had 15 students who had a mean score of 80, and Section B had 20 students who had a mean score of 90.

We know that  , \text{Mean}=\dfrac{\text{Sum of observations}}{\text{No. of observations}}

Then , for section A :

\text{Mean score }=\dfrac{\text{Sum of scores in sec A}}{\text{No. of students}}

\Rightarrow\ 80=\dfrac{\text{Sum of scores in sec A}}{15}\\\\\Rightarrow\ \text{Sum of scores in sec A}=80\times15=1200

Similarly in Section B, \text{Sum of scores in sec B}=90\times20=1800

Total scores = Sum of scores in sec A+Sum of scores in sec B

=1200+1800=3000

Total students = Students in sec A +Students in sec B

=15+20=35

Now , the mean score for all of the students on the quiz =\dfrac{\text{Total score}}{\text{Total students}}

=\dfrac{3000}{35}=85.7142857143\approx85.7

Hence, the approximate mean score for all of the students on the quiz = 85.7

Thus , the correct answer is option A. 85.7.

7 0
2 years ago
If you apply the changes below to the linear parent function, Fx) = x, what is
Inga [223]

Answer: A. G(x)= ax=y= - f(x) is flip over x-axis. Therefore, f(x) =14x would become f(x) =-14x. Therefore, final transformed function f(x)=-14x is vertically stretch by a factor of 14 and flip over the x-axis.

5 0
3 years ago
In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
7nadin3 [17]

Correct answer is: distance from D to AB is 6cm

Solution:-

Let us assume E is the altitude drawn from D to AB.

Given that m∠ACB=120° and ABC is isosceles which means

m∠ABC=m∠BAC = \frac{180-120}{2}=30

And AC= BC

Let AC=BC=x

Then from ΔACD , cos(∠ACD) = \frac{DC}{AC} =\frac{4}{x}

Since DCB is a straight line m∠ACD+m∠ACB =180

                                              m∠ACD = 180-m∠ACB = 60

Hence cos(60)=\frac{4}{x}

          x=\frac{4}{cos60}= 8

Now let us consider ΔBDE, sin(∠DBE) = \frac{DE}{DB} =\frac{DE}{DA+AB} = \frac{DE}{4+8}

DE = 12sin(30) = 6cm

7 0
3 years ago
Determine whether a relation is a function, as well as its domain and range: State the domain and range for the function f(x)=x^
Anna35 [415]
F(x) = x^2 + 3 is a function.
domain of f(x) = x^2 + 3 is all real numbers.
range is all real numbers greater or equal to 3.
6 0
3 years ago
Read 2 more answers
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