We have that (x) + (x+2) + (x+4) = 126 so 3x + 6 = 126 can be used to find the first integer.
3x + 6 = 126
3x = 120
x = 40
The numbers are 40, 42, 44
Well, we can find the answer by multiplying the two fractions. 3/4*1/8 equals 3/32.
Combined like terms 11d+8
Answer:
Addition prop of equality, multiplication prop of equality, multiplication prop. of equality
Step-by-step explanation:
For the first one, we know that in order to solve the equation, we need to add 3 to both sides of the equation. When you add a value to both sides of the equation, you're using the addition property of equality.
For the second one, we know that in order to solve the equation, we need to multiply both side by 1/6 (to cancel the 6 out on the left side). When you multiply something to both sides of the equation, you're using the multiplication property of equality.
For the third one, we know that in order to solve the equation, we must multiply both sides of the equation by 5. Like the second problem, this would be the multiplication property of equality (since you're multiplying both sides of the equation by the same thing).
