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3 years ago

(7th grade work) How many gallons of water were in the bucket after 1 second? Explain your thinking.

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

6 0

Answer:0.5, half a gallon

Step-by-step explanation:

Illusion [34]3 years ago

5 0

Answer:

.5 half a gallon bc as you can see in the graph there is only half

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What value of g makes the equation 2g+6-14g=-6(g-5) true?

Sergeu [11.5K]

Answer:

g=-4

Step-by-step explanation:

2g+6-14g=-6(g-5)

-12g+6=-6g+30

-6g+6=30

-6g=24

g=-4

8 0

3 years ago

2. Two angles have a common vertex but no common side. How can you tell whether the angles are vertical angles?

Maksim231197 [3]

Explanation:

The angles are <em>vertical angles</em> if the opposites of the rays forming one of the angles are the rays forming the other angle.

More formally, if V is the common vertex, and ...

R is a point on one of the rays forming Angle 1
S is a point on the ray that is the opposite of ray VR
T is a point on the other ray forming Angle 1
U is a point on the ray that is the opposite of ray VT

Then angle RVT and angle SVU are vertical angles.

___

Another way to say this is that points R, V, S are collinear, as are points T, V, U, and the two angles of interest are RVT and SVU.

If the above conditions cannot be met, then the angles are not vertical angles.

7 0

3 years ago

1. Find the lengths of the missing sides in the pairs of s 5 X 4 2 3 7

Ahat [919]

Answer:

21185

Step-by-step explanation:

7 0

2 years ago

WILL GIVE BRAINLIEST

Ray Of Light [21]

Answer:

(x,y) --> (x, y-5)

Step-by-step explanation:

the y-intercept of f(x) = (0,2)

the y-intercept of g(x) = (0, -3)

-3 - 2 = -5

4 0

3 years ago

Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value $t_{0}$ falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by $2P(T$ 0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}$ , i.e.,

$-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}$

where $t_{0.025}$ is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

$-0.03\pm(2.0167)(0.012459)(0.3)$ , i.e.,

(-0.0225, -0.0375)

8 0

3 years ago