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just olya [345]
3 years ago
6

7x+4y-6z=-73 8x+5y+6z=-59 -4x-8y-3z=46 y=

Mathematics
1 answer:
Oksanka [162]3 years ago
5 0
Is this all one equation??
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Ava and Kelly ran a road race, starting from the same place at the same time. Ava ran at an average speed of 6 miles per hour. K
zalisa [80]
<h2>Hello!</h2>

The answer is:

It will took 0.375 hours for Ava and Kelly to be 3/4 miles apart.

<h2>Why?</h2>

To calculate how long after they start they will be 3/4 miles apart, we need to write two equations.

So, writing the equations, we have:

Calculations for Ava:

We have the following information,

v_{Ava}=6mph

Then, writing the equation,

x_{Ava}=x_{o}+v_{Ava}*t

x_{Ava}=x_{o}+v_{6mph}*t

Calculations for Kelly:

We have the following information,

v_{Kelly}=8mph

We need to calculate when Kelly will be 3/4 miles apart of Ava, so, it's position will be the Ava's position plus 3/4 miles.

Then, writing the equation,

x_{Ava}+0.75miles=x_{o}+v_{Kelly}*t

x_{Ava}+0.75miles=x_{o}+v_{8mph}*t

Now, substituting Ava's speed into the second equation, we have:

x_{o}+6mph*t+0.75miles=x_{o}+8mph*t

6mph*t+0.75miles=+8mph*t

8mph*t-6mph*t=0.75miles

2mph*t=0.75miles

t=\frac{0.75miles}{2mph}=0.375hours

Hence, we have that it will took 0.375 hours for Ava and Kelly to be 3/4 miles apart.

Have a nice day!

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3 years ago
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What are 1x3 and 1x3 combined?
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Answer:

it would be 6

Step-by-step explanation:

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10 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

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Write 0.002358 in scientific notation.
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