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Bogdan [553]
3 years ago
15

X+5÷9=3 What is the number where when you add 5 then divide it by 9 it is 3?

Mathematics
2 answers:
Verdich [7]3 years ago
5 0

Answer:

Step-by-step explanation:

(X + 5)/9 = 3

Cross multiply

X + 5 = 3(9)

X + 5 = 27

X = 27 - 5

X = 22

Karo-lina-s [1.5K]3 years ago
4 0
Exact form: x=22/9 Decimal Form: x= 2.4 Mixed number form: x= 2 4/9
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(7)/(3) of it is 5 (5)/(6)
slava [35]

let's firstly convert the mixed fraction to improper fraction and then take it from there, keeping in mind that the whole is "x".

\stackrel{mixed}{5\frac{5}{6}}\implies \cfrac{5\cdot 6+5}{6}\implies \stackrel{improper}{\cfrac{35}{6}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{7}{3}x~~ = ~~5\frac{5}{6}\implies \cfrac{7}{3}x~~ = ~~\cfrac{35}{6}\implies 42x=105\implies x=\cfrac{105}{42} \\\\\\ x=\cfrac{21\cdot 5}{21\cdot 2}\implies x=\cfrac{21}{21}\cdot \cfrac{5}{2}\implies x=1\cdot \cfrac{5}{2}\implies x=2\frac{1}{2}

7 0
2 years ago
Solution for dy/dx+xsin 2 y=x^3 cos^2y
vichka [17]
Rearrange the ODE as

\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y=x^3\cos^2y
\sec^2y\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y\sec^2y=x^3

Take u=\tan y, so that \dfrac{\mathrm du}{\mathrm dx}=\sec^2y\dfrac{\mathrm dy}{\mathrm dx}.

Supposing that |y|, we have \tan^{-1}u=y, from which it follows that

\sin2y=2\sin y\cos y=2\dfrac u{\sqrt{u^2+1}}\dfrac1{\sqrt{u^2+1}}=\dfrac{2u}{u^2+1}
\sec^2y=1+\tan^2y=1+u^2

So we can write the ODE as

\dfrac{\mathrm du}{\mathrm dx}+2xu=x^3

which is linear in u. Multiplying both sides by e^{x^2}, we have

e^{x^2}\dfrac{\mathrm du}{\mathrm dx}+2xe^{x^2}u=x^3e^{x^2}
\dfrac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]=x^3e^{x^2}

Integrate both sides with respect to x:

\displaystyle\int\frac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]\,\mathrm dx=\int x^3e^{x^2}\,\mathrm dx
e^{x^2}u=\displaystyle\int x^3e^{x^2}\,\mathrm dx

Substitute t=x^2, so that \mathrm dt=2x\,\mathrm dx. Then

\displaystyle\int x^3e^{x^2}\,\mathrm dx=\frac12\int 2xx^2e^{x^2}\,\mathrm dx=\frac12\int te^t\,\mathrm dt

Integrate the right hand side by parts using

f=t\implies\mathrm df=\mathrm dt
\mathrm dg=e^t\,\mathrm dt\implies g=e^t
\displaystyle\frac12\int te^t\,\mathrm dt=\frac12\left(te^t-\int e^t\,\mathrm dt\right)

You should end up with

e^{x^2}u=\dfrac12e^{x^2}(x^2-1)+C
u=\dfrac{x^2-1}2+Ce^{-x^2}
\tan y=\dfrac{x^2-1}2+Ce^{-x^2}

and provided that we restrict |y|, we can write

y=\tan^{-1}\left(\dfrac{x^2-1}2+Ce^{-x^2}\right)
5 0
3 years ago
Please help ASAP!!!!
horrorfan [7]
1. The withdrawals adds up to 291+99+150+12= 552
500-552= -52
2. The bus pass which cost $150.
3.1000-552= $448 left
4.1000-552-300-150=$-2 left. Withdrawal had happened.
8 0
3 years ago
Which of the expressions below could be factored quickly using the "difference of squares"? Select all that apply.
boyakko [2]

Answer:

Difference of squares method is a method that is used to evaluate the difference between two perfect squares.

For example, given an algebraic expression in the form:

can be factored as follows:

From the given expressions, the only expression containing two perfect squares with the minus sign in the middle is the expression in option A.

i.e.  

which can be factored as follows:

.

3 0
3 years ago
Read 2 more answers
Find MQ in parallelogram LMNQ .
Liula [17]

Answer:

MQ = 16.4

By the <u>Parallelogram Diagonals Theorem</u> , MP = <u>PQ</u>

So MQ = 2 · <u>MP</u>

<u />

Step-by-step explanation:

<u>Parallelogram Diagonals Theorem</u>

The diagonals of a parallelogram bisect each other, i.e. they divide each other into <em>two equal parts</em>.

P is the point of intersection of the diagonals.

Therefore, MP = PQ and LP = PN

If MP = 8.2, then PQ = 8.2

⇒ MQ = 8.2 + 8.2 = 16.4

8 0
2 years ago
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