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mel-nik [20]
3 years ago
13

How to solve 2(x+y)^2-9(x+y)-5​

Mathematics
1 answer:
Aliun [14]3 years ago
6 0

Answer:

2(x + y)² - 9( x + y ) -5 = 0

⇒2(x + y)² - 10 (x+y) +1(x+y) -5 = 0

⇒2(x+y)(x + y - 5 ) + 1(x + y -5 ) = 0

taking (x + y -5 ) common , 

⇒(x + y -5 )[2(x + y) + 1]  =0 

⇒(x + y -5)(2x + 2y +1) =0

hope , you got this 

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you accidentally dropped a coin from the top of 10 stairs. what is the probability that it will land on the 4th step facing up
Roman55 [17]

Answer:

Step-by-step explanation:

1/10 * 1/4 = 1/14

1/2 because there is a 50/50% chance its either heads or tails

3 0
3 years ago
What is equivalent to 3 to the negative 2nd power
VladimirAG [237]
3 to the negative second power is written like this: 3^{-2}. 

When simplifying an expression with a negative exponent, you take a positive version of the exponent, in this case that would be 2, and apply that to the base. 
After doing that, we have 9. 
The next step is to put one over that number.
In this case, now after doing that the answer is \frac{1}{9}. 

Hope this helps!
6 0
3 years ago
What two rational expressions sum to 2x+3/x^2-5x+4
Anni [7]

Answer:

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

Step-by-step explanation:

Given the rational expression: \frac{2x + 3}{x^2 - 5x + 4}, to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

x^2 - 5x + 4

x^2 - 4x - x + 4

(x^2 - 4x) - (x + 4)

x(x - 4) - 1(x - 4)

(x- 1)(x - 4)

Thus, we now have: \frac{2x + 3}{(x- 1)(x - 4)}

Step 2: Apply the concept of Partial Fraction

Let,

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

Multiply both sides by (x - 1)(x - 4)

\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4) = (\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)

2x + 3 = A(x - 4) + B(x - 1)

Step 3:

Substituting x = 4 in 2x + 3 = A(x - 4) + B(x - 1)

2(4) + 3 = A(4 - 4) + B(4 - 1)

8 + 3 = A(0) + B(3)

11 = 3B

\frac{11}{3} = B

B = \frac{11}{3}

Substituting x = 1 in 2x + 3 = A(x - 4) + B(x - 1)

2(1) + 3 = A(1 - 4) + B(1 - 1)

2 + 3 = A(-3) + B(0)

5 = -3A

\frac{5}{-3} = \frac{-3A}{-3}

A = -\frac{5}{3}

Step 4: Plug in the values of A and B into the original equation in step 2

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

7 0
2 years ago
Solve for x.<br> 5x – 31 = 23 - X<br> x = [?]
sergejj [24]

Answer:

X=9

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Find the solution of the system of equations.
Katyanochek1 [597]

Answer:

x = -5

y = -1

Step-by-step explanation:

here's the solution :-

  • subtracting equation 1 from equation 2 we get,

=》-8x - 4y + 8x - 6y = 44 - 34

=》-10y = 10

=》y = -1

plugging the value of y in equation 2 we get :-

=》-8x - 4y = 44

=》-8x - (4 × -1) = 44

=》-8x + 4 = 44

=》x = 40 ÷ -8

=》x = -5

8 0
3 years ago
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