The weight average of the coordinates is -4
<h3>How to determine the
weight average?</h3>
The complete question is given as:
The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. And we need to calculate the weight average
The given parameters are:
- Coordinate -6 has a weight of 3
- Coordinate 2 has a weight of 1.
The weight average is then calculated as:
Weight average = Sum of (Weigh * Coordinate)/Sum of Weights
So, we have:
Weight average = (-6 * 3 + 2 * 1)/(3 +1)
Evaluate the products
Weight average = (-18 + 2)/(3 +1)
Evaluate the sum
Weight average = -16/4
Evaluate the quotient
Weight average = -4
Hence, the weight average of the coordinates is -4
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<u>Complete question</u>
The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. Calculate the weight average
3x + 4y = 16 Write original equation
3x + 4y - 4y = -4y + 16 Subtract 4y from each side
3x = -4y +16 Simplify
3x/3 = -4y/3 + 16/3 Divide each side by three
x = -4y/3 +16/3 Simplify
I hope this helps!
Answer:
1. 180
2. x = 31
Step-by-step explanation:
1. the sum of the interior angles of every triangle is always 180
2. using what we know from problem 1, we can create an equation:
x + 10 + 2x - 5 + 2x + 20 = 180
add like terms: 5x + 25 = 180
subtract 25 from both sides: 5x = 155
divide both sides by 5: x = 31
Answer:
12
Step-by-step explanation:
a2+b2=c2 since the hypotenuse is 13 you would square it to get 169 and then you would square 5 and get 25 you would subtract 169-25 and get 144 then you would square root that number and get 12 so then your answer is 12 in.